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Solve x⁴ + 15x³ + 83x² + 201x + 180 = 0

The solutions of x⁴ + 15x³ + 83x² + 201x + 180 = 0 are x = -5, -4, -3, -3 (repeated roots counted once each: -5, -4, -3).

Graph of y = x⁴ + 15x³ + 83x² + 201x + 180-6.5-6-5.5-5-4.5-4-3.5-3-2.5-2-1.510203040x = -5x = -4x = -3y
Graph of y = x⁴ + 15x³ + 83x² + 201x + 180. The curve crosses the x-axis at x = -5, x = -4, x = -3, the roots found above.

How to work it out

  1. 1

    A quartic has up to 4 real roots. The rational root theorem says that any integer root of a polynomial with integer coefficients and leading coefficient 1 divides the constant term 180, so the candidates are ±1, ±2, ±3, ±4, ±5, ±6, ±9, ±10, ±12, ±15, ±18, ±20, ±30, ±36, ±45, ±60, ±90, ±180.

    x4+15x3+83x2+201x+180=0x^{4} + 15x^{3} + 83x^{2} + 201x + 180 = 0
  2. 2

    Test the candidates until one gives 0. x = -3 is a root. Divide by (x + 3) with synthetic division; the bottom row is the quotient and a 0 remainder.

    −3115832011800−3−36−141−18011247600\begin{array}{c|ccccc} -3 & 1 & 15 & 83 & 201 & 180 \\ & 0 & -3 & -36 & -141 & -180 \\ \hline & 1 & 12 & 47 & 60 & 0 \end{array}
  3. 3

    x = -3 is a root. Divide by (x + 3) with synthetic division; the bottom row is the quotient and a 0 remainder.

    −311247600−3−27−6019200\begin{array}{c|cccc} -3 & 1 & 12 & 47 & 60 \\ & 0 & -3 & -27 & -60 \\ \hline & 1 & 9 & 20 & 0 \end{array}
  4. 4

    What is left is the quadratic x² + 9x + 20 = 0. Solve it (factoring or the quadratic formula):

    x2+9x+20=0⇒x=−4, −5x^{2} + 9x + 20 = 0 \Rightarrow x = -4,\ -5
  5. 5

    So the polynomial factors as

    x4+15x3+83x2+201x+180=(x+5)(x+4)(x+3)2x^{4} + 15x^{3} + 83x^{2} + 201x + 180 = (x + 5)(x + 4)(x + 3)^{2}
LaTeX source of the formulas on this page
\[ x^{4} + 15x^{3} + 83x^{2} + 201x + 180 = (x + 5)(x + 4)(x + 3)^{2} = 0 \]
\[ x^{4} + 15x^{3} + 83x^{2} + 201x + 180 = 0 \]
\[ \begin{array}{c|ccccc} -3 & 1 & 15 & 83 & 201 & 180 \\ & 0 & -3 & -36 & -141 & -180 \\ \hline & 1 & 12 & 47 & 60 & 0 \end{array} \]
\[ \begin{array}{c|cccc} -3 & 1 & 12 & 47 & 60 \\ & 0 & -3 & -27 & -60 \\ \hline & 1 & 9 & 20 & 0 \end{array} \]
\[ x^{2} + 9x + 20 = 0 \Rightarrow x = -4,\ -5 \]
\[ x^{4} + 15x^{3} + 83x^{2} + 201x + 180 = (x + 5)(x + 4)(x + 3)^{2} \]

Candidates tested (computed)

Candidate xp(x)Root?
1480no
-148no
21050no
-26no
32016no
-30root

Vieta's formulas check the answer (computed)

RelationFrom the rootsFrom the coefficients
Sum of the roots-15-15
Product of the roots180180

Questions

What are the roots of x⁴ + 15x³ + 83x² + 201x + 180 = 0?

The solutions of x⁴ + 15x³ + 83x² + 201x + 180 = 0 are x = -5, -4, -3, -3 (repeated roots counted once each: -5, -4, -3).

How do you factor x⁴ + 15x³ + 83x² + 201x + 180?

(x + 5)(x + 4)(x + 3).

What is the sum of the roots?

-15 (it equals −15 by Vieta's formulas).

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    Solve x⁴ + 15x³ + 83x² + 201x + 180 = 0: x = -5, -4, -3 | WordGPT