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Solve -3x² - 6x + 6 = 0

The solutions of -3x² - 6x + 6 = 0 are x = -1 + √3 or x = -1 - √3, that is x ≈ -2.7320508 and x ≈ 0.73205081.

x² +x += 0
−3x2−6x+6=0⇒x=−1+3, −1−3-3x^2 - 6x + 6 = 0 \Rightarrow x = -1 + \sqrt{3},\ -1 - \sqrt{3}
Discriminant D = 108 · x ≈ -2.73205, 0.732051

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = -3x² - 6x + 6-5-4-3-2-1123-40-30-20-1010x = -2.7320508x = 0.73205081vertexy = -3x² - 6x + 6
Graph of y = -3x² - 6x + 6. The curve crosses the x-axis at x = -2.7320508 and x = 0.73205081; the vertex is at (-1, 9).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -3, b = -6, c = 6.

    −3x2−6x+6=0-3x^2 - 6x + 6 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−6)2−4⋅(−3)⋅6=36+72=108D = (-6)^2 - 4\cdot(-3)\cdot6 = 36 + 72 = 108
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=6±108−6x = \frac{-b \pm \sqrt{D}}{2a} = \frac{6 \pm \sqrt{108}}{-6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−1+3orx=−1−3x = -1 + \sqrt{3}\quad\text{or}\quad x = -1 - \sqrt{3}
  6. 6

    As decimals: x ≈ -2.7320508 and x ≈ 0.73205081.

  7. 7

    Check numerically: for x ≈ -2.7320508 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ -3x^2 - 6x + 6 = 0\ \Rightarrow\ x = -1 + \sqrt{3},\ -1 - \sqrt{3} \]
\[ -3x^2 - 6x + 6 = 0 \]
\[ D = (-6)^2 - 4\cdot(-3)\cdot6 = 36 + 72 = 108 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{6 \pm \sqrt{108}}{-6} \]
\[ x = -1 + \sqrt{3}\quad\text{or}\quad x = -1 - \sqrt{3} \]

The parabola y = -3x² - 6x + 6

xy
-4-18
-3-3
-26
-19
06
1-3
2-18

Questions

What are the solutions of -3x² - 6x + 6 = 0?

The solutions of -3x² - 6x + 6 = 0 are x = -1 + √3 or x = -1 - √3, that is x ≈ -2.7320508 and x ≈ 0.73205081.

Does -3x² - 6x + 6 = 0 factor?

Not over the integers, because the discriminant 108 is not a perfect square. Use the quadratic formula.

What is the vertex of y = -3x² - 6x + 6?

(-1, 9). The parabola opens downwards, so this is the maximum.

What are the sum and product of the roots?

Sum = −b/a = -2, product = c/a = -2.

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    Solve -3x² - 6x + 6 = 0: x = -1 + √3 or x = -1 - √3 (steps) | WordGPT