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Solve -3x² - 6x + 3 = 0

The solutions of -3x² - 6x + 3 = 0 are x = -1 + √2 or x = -1 - √2, that is x ≈ -2.4142136 and x ≈ 0.41421356.

x² +x += 0
−3x2−6x+3=0⇒x=−1+2, −1−2-3x^2 - 6x + 3 = 0 \Rightarrow x = -1 + \sqrt{2},\ -1 - \sqrt{2}
Discriminant D = 72 · x ≈ -2.41421, 0.414214

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = -3x² - 6x + 3-4-3-2-112-40-30-20-1010x = -2.4142136x = 0.41421356vertexy = -3x² - 6x + 3
Graph of y = -3x² - 6x + 3. The curve crosses the x-axis at x = -2.4142136 and x = 0.41421356; the vertex is at (-1, 6).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -3, b = -6, c = 3.

    −3x2−6x+3=0-3x^2 - 6x + 3 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−6)2−4⋅(−3)⋅3=36+36=72D = (-6)^2 - 4\cdot(-3)\cdot3 = 36 + 36 = 72
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=6±72−6x = \frac{-b \pm \sqrt{D}}{2a} = \frac{6 \pm \sqrt{72}}{-6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−1+2orx=−1−2x = -1 + \sqrt{2}\quad\text{or}\quad x = -1 - \sqrt{2}
  6. 6

    As decimals: x ≈ -2.4142136 and x ≈ 0.41421356.

  7. 7

    Check numerically: for x ≈ -2.4142136 the left side is 1.7763568e-15 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ -3x^2 - 6x + 3 = 0\ \Rightarrow\ x = -1 + \sqrt{2},\ -1 - \sqrt{2} \]
\[ -3x^2 - 6x + 3 = 0 \]
\[ D = (-6)^2 - 4\cdot(-3)\cdot3 = 36 + 36 = 72 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{6 \pm \sqrt{72}}{-6} \]
\[ x = -1 + \sqrt{2}\quad\text{or}\quad x = -1 - \sqrt{2} \]

The parabola y = -3x² - 6x + 3

xy
-4-21
-3-6
-23
-16
03
1-6
2-21

Questions

What are the solutions of -3x² - 6x + 3 = 0?

The solutions of -3x² - 6x + 3 = 0 are x = -1 + √2 or x = -1 - √2, that is x ≈ -2.4142136 and x ≈ 0.41421356.

Does -3x² - 6x + 3 = 0 factor?

Not over the integers, because the discriminant 72 is not a perfect square. Use the quadratic formula.

What is the vertex of y = -3x² - 6x + 3?

(-1, 6). The parabola opens downwards, so this is the maximum.

What are the sum and product of the roots?

Sum = −b/a = -2, product = c/a = -1.

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    Solve -3x² - 6x + 3 = 0: x = -1 + √2 or x = -1 - √2 (steps) | WordGPT