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Solve -3x² - 5x - 10 = 0

-3x² - 5x - 10 = 0 has no real solutions. The two complex solutions are x = (-5 + √95 i)/6 and x = (-5 - √95 i)/6.

x² +x += 0
−3x2−5x−10=0⇒x=−5+95 i6, −5−95 i6 (complex)-3x^2 - 5x - 10 = 0 \Rightarrow x = \frac{-5 + \sqrt{95}\, i}{6},\ \frac{-5 - \sqrt{95}\, i}{6}\ \text{(complex)}
Discriminant D = -95

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = -3x² - 5x - 10-4-3-2-1123-50-40-30-20-10vertexy = -3x² - 5x - 10
Graph of y = -3x² - 5x - 10. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (-0.83333333, -7.9166667).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -3, b = -5, c = -10.

    −3x2−5x−10=0-3x^2 - 5x - 10 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−5)2−4⋅(−3)⋅(−10)=25−120=−95D = (-5)^2 - 4\cdot(-3)\cdot(-10) = 25 - 120 = -95
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=5±−95−6x = \frac{-b \pm \sqrt{D}}{2a} = \frac{5 \pm \sqrt{-95}}{-6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−5+95 i6orx=−5−95 i6x = \frac{-5 + \sqrt{95}\, i}{6}\quad\text{or}\quad x = \frac{-5 - \sqrt{95}\, i}{6}
LaTeX source of the formulas on this page
\[ -3x^2 - 5x - 10 = 0\ \Rightarrow\ x = \frac{-5 + \sqrt{95}\, i}{6},\ \frac{-5 - \sqrt{95}\, i}{6} \]
\[ -3x^2 - 5x - 10 = 0 \]
\[ D = (-5)^2 - 4\cdot(-3)\cdot(-10) = 25 - 120 = -95 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{5 \pm \sqrt{-95}}{-6} \]
\[ x = \frac{-5 + \sqrt{95}\, i}{6}\quad\text{or}\quad x = \frac{-5 - \sqrt{95}\, i}{6} \]

The parabola y = -3x² - 5x - 10

xy
-3.8333-34.916067
-2.8333-19.916267
-1.8333-10.916467
-0.8333-7.9166667
0.1667-10.916867
1.1667-19.917067
2.1667-34.917267

Questions

What are the solutions of -3x² - 5x - 10 = 0?

-3x² - 5x - 10 = 0 has no real solutions. The two complex solutions are x = (-5 + √95 i)/6 and x = (-5 - √95 i)/6.

Does -3x² - 5x - 10 = 0 factor?

Not over the integers, because the discriminant -95 is negative. Use the quadratic formula.

What is the vertex of y = -3x² - 5x - 10?

(-5/6, -95/12). The parabola opens downwards, so this is the maximum.

What are the sum and product of the roots?

Sum = −b/a = -5/3, product = c/a = 10/3.

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