Solve -3x² + 3x + 3 = 0
The solutions of -3x² + 3x + 3 = 0 are x = (1 + √5)/2 or x = (1 - √5)/2, that is x ≈ -0.61803399 and x ≈ 1.618034.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -3, b = 3, c = 3.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
The quadratic formula works for every quadratic:
- 5
Simplify (pull the square out of the root) to get the solutions:
- 6
As decimals: x ≈ -0.61803399 and x ≈ 1.618034.
- 7
Check numerically: for x ≈ -0.61803399 the left side is -4.4408921e-16 (zero up to rounding) ✓
LaTeX source of the formulas on this page
\[ -3x^2 + 3x + 3 = 0\ \Rightarrow\ x = \frac{1 + \sqrt{5}}{2},\ \frac{1 - \sqrt{5}}{2} \]
\[ -3x^2 + 3x + 3 = 0 \]
\[ D = 3^2 - 4\cdot(-3)\cdot3 = 9 + 36 = 45 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-3 \pm \sqrt{45}}{-6} \]
\[ x = \frac{1 + \sqrt{5}}{2}\quad\text{or}\quad x = \frac{1 - \sqrt{5}}{2} \]The parabola y = -3x² + 3x + 3
| x | y |
|---|---|
| -2.5 | -23.25 |
| -1.5 | -8.25 |
| -0.5 | 0.75 |
| 0.5 | 3.75 |
| 1.5 | 0.75 |
| 2.5 | -8.25 |
| 3.5 | -23.25 |
Questions
What are the solutions of -3x² + 3x + 3 = 0?
The solutions of -3x² + 3x + 3 = 0 are x = (1 + √5)/2 or x = (1 - √5)/2, that is x ≈ -0.61803399 and x ≈ 1.618034.
Does -3x² + 3x + 3 = 0 factor?
Not over the integers, because the discriminant 45 is not a perfect square. Use the quadratic formula.
What is the vertex of y = -3x² + 3x + 3?
(1/2, 15/4). The parabola opens downwards, so this is the maximum.
What are the sum and product of the roots?
Sum = −b/a = 1, product = c/a = -1.