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Solve -2x² - 2x + 12 = 0

The solutions of -2x² - 2x + 12 = 0 are x = -3 or x = 2.

x² +x += 0
−2x2−2x+12=0⇒x=−3, 2-2x^2 - 2x + 12 = 0 \Rightarrow x = -3,\ 2
Discriminant D = 100 · x ≈ -3, 2

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = -2x² - 2x + 12-5-4-3-2-11234-40-30-20-1010x = -3x = 2vertexy = -2x² - 2x + 12
Graph of y = -2x² - 2x + 12. The curve crosses the x-axis at x = -3 and x = 2; the vertex is at (-0.5, 12.5).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -2, b = -2, c = 12.

    −2x2−2x+12=0-2x^2 - 2x + 12 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−2)2−4⋅(−2)⋅12=4+96=100D = (-2)^2 - 4\cdot(-2)\cdot12 = 4 + 96 = 100
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    Method 1, factoring. The roots are rational, so the left side factors:

    −2(x+3)(x−2)=0-2\left(x + 3\right)\left(x - 2\right) = 0
  5. 5

    A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:

    x+3=0⇒x=−3x−2=0⇒x=2x + 3 = 0 \Rightarrow x = -3\qquad x - 2 = 0 \Rightarrow x = 2
  6. 6

    Method 2, The quadratic formula works for every quadratic:

    x=−b±D2a=2±100−4x = \frac{-b \pm \sqrt{D}}{2a} = \frac{2 \pm \sqrt{100}}{-4}
  7. 7

    Simplify to get the solutions:

    x=−3orx=2x = -3\quad\text{or}\quad x = 2
  8. 8

    Check by putting x = -3 back in: a·x² + b·x + c = -2·(9) + (-2)·(-3) + 12 = 0 ✓

LaTeX source of the formulas on this page
\[ -2x^2 - 2x + 12 = 0\ \Rightarrow\ x = -3,\ 2 \]
\[ -2x^2 - 2x + 12 = 0 \]
\[ D = (-2)^2 - 4\cdot(-2)\cdot12 = 4 + 96 = 100 \]
\[ -2\left(x + 3\right)\left(x - 2\right) = 0 \]
\[ x + 3 = 0 \Rightarrow x = -3\qquad x - 2 = 0 \Rightarrow x = 2 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{2 \pm \sqrt{100}}{-4} \]
\[ x = -3\quad\text{or}\quad x = 2 \]

The parabola y = -2x² - 2x + 12

xy
-3.5-5.5
-2.54.5
-1.510.5
-0.512.5
0.510.5
1.54.5
2.5-5.5

Questions

What are the solutions of -2x² - 2x + 12 = 0?

The solutions of -2x² - 2x + 12 = 0 are x = -3 or x = 2.

Does -2x² - 2x + 12 = 0 factor?

Yes: -2(x+3)(x-2) = 0.

What is the vertex of y = -2x² - 2x + 12?

(-1/2, 25/2). The parabola opens downwards, so this is the maximum.

What are the sum and product of the roots?

Sum = −b/a = -1, product = c/a = -6.

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