Solve -2x² - 10x + 6 = 0
The solutions of -2x² - 10x + 6 = 0 are x = (-5 + √37)/2 or x = (-5 - √37)/2, that is x ≈ -5.5413813 and x ≈ 0.54138127.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -2, b = -10, c = 6.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
The quadratic formula works for every quadratic:
- 5
Simplify (pull the square out of the root) to get the solutions:
- 6
As decimals: x ≈ -5.5413813 and x ≈ 0.54138127.
- 7
Check numerically: for x ≈ -5.5413813 the left side is 7.1054274e-15 (zero up to rounding) ✓
LaTeX source of the formulas on this page
\[ -2x^2 - 10x + 6 = 0\ \Rightarrow\ x = \frac{-5 + \sqrt{37}}{2},\ \frac{-5 - \sqrt{37}}{2} \]
\[ -2x^2 - 10x + 6 = 0 \]
\[ D = (-10)^2 - 4\cdot(-2)\cdot6 = 100 + 48 = 148 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{148}}{-4} \]
\[ x = \frac{-5 + \sqrt{37}}{2}\quad\text{or}\quad x = \frac{-5 - \sqrt{37}}{2} \]The parabola y = -2x² - 10x + 6
| x | y |
|---|---|
| -5.5 | 0.5 |
| -4.5 | 10.5 |
| -3.5 | 16.5 |
| -2.5 | 18.5 |
| -1.5 | 16.5 |
| -0.5 | 10.5 |
| 0.5 | 0.5 |
Questions
What are the solutions of -2x² - 10x + 6 = 0?
The solutions of -2x² - 10x + 6 = 0 are x = (-5 + √37)/2 or x = (-5 - √37)/2, that is x ≈ -5.5413813 and x ≈ 0.54138127.
Does -2x² - 10x + 6 = 0 factor?
Not over the integers, because the discriminant 148 is not a perfect square. Use the quadratic formula.
What is the vertex of y = -2x² - 10x + 6?
(-5/2, 37/2). The parabola opens downwards, so this is the maximum.
What are the sum and product of the roots?
Sum = −b/a = -5, product = c/a = -3.