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Solve -2x² - 10x + 12 = 0

The solutions of -2x² - 10x + 12 = 0 are x = -6 or x = 1.

x² +x += 0
−2x2−10x+12=0⇒x=−6, 1-2x^2 - 10x + 12 = 0 \Rightarrow x = -6,\ 1
Discriminant D = 196 · x ≈ -6, 1

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = -2x² - 10x + 12-8-6-4-22-50-40-30-20-10102030x = -6x = 1vertexy = -2x² - 10x + 12
Graph of y = -2x² - 10x + 12. The curve crosses the x-axis at x = -6 and x = 1; the vertex is at (-2.5, 24.5).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -2, b = -10, c = 12.

    −2x2−10x+12=0-2x^2 - 10x + 12 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−10)2−4⋅(−2)⋅12=100+96=196D = (-10)^2 - 4\cdot(-2)\cdot12 = 100 + 96 = 196
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    Method 1, factoring. The roots are rational, so the left side factors:

    −2(x+6)(x−1)=0-2\left(x + 6\right)\left(x - 1\right) = 0
  5. 5

    A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:

    x+6=0⇒x=−6x−1=0⇒x=1x + 6 = 0 \Rightarrow x = -6\qquad x - 1 = 0 \Rightarrow x = 1
  6. 6

    Method 2, The quadratic formula works for every quadratic:

    x=−b±D2a=10±196−4x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{196}}{-4}
  7. 7

    Simplify to get the solutions:

    x=−6orx=1x = -6\quad\text{or}\quad x = 1
  8. 8

    Check by putting x = -6 back in: a·x² + b·x + c = -2·(36) + (-10)·(-6) + 12 = 0 ✓

LaTeX source of the formulas on this page
\[ -2x^2 - 10x + 12 = 0\ \Rightarrow\ x = -6,\ 1 \]
\[ -2x^2 - 10x + 12 = 0 \]
\[ D = (-10)^2 - 4\cdot(-2)\cdot12 = 100 + 96 = 196 \]
\[ -2\left(x + 6\right)\left(x - 1\right) = 0 \]
\[ x + 6 = 0 \Rightarrow x = -6\qquad x - 1 = 0 \Rightarrow x = 1 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{196}}{-4} \]
\[ x = -6\quad\text{or}\quad x = 1 \]

The parabola y = -2x² - 10x + 12

xy
-5.56.5
-4.516.5
-3.522.5
-2.524.5
-1.522.5
-0.516.5
0.56.5

Questions

What are the solutions of -2x² - 10x + 12 = 0?

The solutions of -2x² - 10x + 12 = 0 are x = -6 or x = 1.

Does -2x² - 10x + 12 = 0 factor?

Yes: -2(x+6)(x-1) = 0.

What is the vertex of y = -2x² - 10x + 12?

(-5/2, 49/2). The parabola opens downwards, so this is the maximum.

What are the sum and product of the roots?

Sum = −b/a = -5, product = c/a = -6.

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