Solve -2x² + 12 = 0
The solutions of -2x² + 12 = 0 are x = √6 or x = -√6, that is x ≈ -2.4494897 and x ≈ 2.4494897.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -2, b = 0, c = 12.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
The quadratic formula works for every quadratic:
- 5
Simplify (pull the square out of the root) to get the solutions:
- 6
As decimals: x ≈ -2.4494897 and x ≈ 2.4494897.
- 7
Check numerically: for x ≈ -2.4494897 the left side is 1.7763568e-15 (zero up to rounding) ✓
LaTeX source of the formulas on this page
\[ -2x^2 + 12 = 0\ \Rightarrow\ x = \sqrt{6},\ -\sqrt{6} \]
\[ -2x^2 + 12 = 0 \]
\[ D = 0^2 - 4\cdot(-2)\cdot12 = 0 + 96 = 96 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{0 \pm \sqrt{96}}{-4} \]
\[ x = \sqrt{6}\quad\text{or}\quad x = -\sqrt{6} \]The parabola y = -2x² + 12
| x | y |
|---|---|
| -3 | -6 |
| -2 | 4 |
| -1 | 10 |
| 0 | 12 |
| 1 | 10 |
| 2 | 4 |
| 3 | -6 |
Questions
What are the solutions of -2x² + 12 = 0?
The solutions of -2x² + 12 = 0 are x = √6 or x = -√6, that is x ≈ -2.4494897 and x ≈ 2.4494897.
Does -2x² + 12 = 0 factor?
Not over the integers, because the discriminant 96 is not a perfect square. Use the quadratic formula.
What is the vertex of y = -2x² + 12?
(0, 12). The parabola opens downwards, so this is the maximum.
What are the sum and product of the roots?
Sum = −b/a = 0, product = c/a = -6.