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Solve -x² - 5x - 10 = 0

-x² - 5x - 10 = 0 has no real solutions. The two complex solutions are x = (-5 + √15 i)/2 and x = (-5 - √15 i)/2.

x² +x += 0
−x2−5x−10=0⇒x=−5+15 i2, −5−15 i2 (complex)-x^2 - 5x - 10 = 0 \Rightarrow x = \frac{-5 + \sqrt{15}\, i}{2},\ \frac{-5 - \sqrt{15}\, i}{2}\ \text{(complex)}
Discriminant D = -15

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = -x² - 5x - 10-6-5-4-3-2-11-20-18-16-14-12-10-8-6-4-2vertexy = -x² - 5x - 10
Graph of y = -x² - 5x - 10. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (-2.5, -3.75).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -1, b = -5, c = -10.

    −x2−5x−10=0-x^2 - 5x - 10 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−5)2−4⋅(−1)⋅(−10)=25−40=−15D = (-5)^2 - 4\cdot(-1)\cdot(-10) = 25 - 40 = -15
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=5±−15−2x = \frac{-b \pm \sqrt{D}}{2a} = \frac{5 \pm \sqrt{-15}}{-2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−5+15 i2orx=−5−15 i2x = \frac{-5 + \sqrt{15}\, i}{2}\quad\text{or}\quad x = \frac{-5 - \sqrt{15}\, i}{2}
LaTeX source of the formulas on this page
\[ -x^2 - 5x - 10 = 0\ \Rightarrow\ x = \frac{-5 + \sqrt{15}\, i}{2},\ \frac{-5 - \sqrt{15}\, i}{2} \]
\[ -x^2 - 5x - 10 = 0 \]
\[ D = (-5)^2 - 4\cdot(-1)\cdot(-10) = 25 - 40 = -15 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{5 \pm \sqrt{-15}}{-2} \]
\[ x = \frac{-5 + \sqrt{15}\, i}{2}\quad\text{or}\quad x = \frac{-5 - \sqrt{15}\, i}{2} \]

The parabola y = -x² - 5x - 10

xy
-5.5-12.75
-4.5-7.75
-3.5-4.75
-2.5-3.75
-1.5-4.75
-0.5-7.75
0.5-12.75

Questions

What are the solutions of -x² - 5x - 10 = 0?

-x² - 5x - 10 = 0 has no real solutions. The two complex solutions are x = (-5 + √15 i)/2 and x = (-5 - √15 i)/2.

Does -x² - 5x - 10 = 0 factor?

Not over the integers, because the discriminant -15 is negative. Use the quadratic formula.

What is the vertex of y = -x² - 5x - 10?

(-5/2, -15/4). The parabola opens downwards, so this is the maximum.

What are the sum and product of the roots?

Sum = −b/a = -5, product = c/a = 10.

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