Solve -x² - 12x + 7 = 0
The solutions of -x² - 12x + 7 = 0 are x = -6 + √43 or x = -6 - √43, that is x ≈ -12.557439 and x ≈ 0.55743852.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -1, b = -12, c = 7.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
The quadratic formula works for every quadratic:
- 5
Simplify (pull the square out of the root) to get the solutions:
- 6
As decimals: x ≈ -12.557439 and x ≈ 0.55743852.
- 7
Check numerically: for x ≈ -12.557439 the left side is 0 (zero up to rounding) ✓
LaTeX source of the formulas on this page
\[ -x^2 - 12x + 7 = 0\ \Rightarrow\ x = -6 + \sqrt{43},\ -6 - \sqrt{43} \]
\[ -x^2 - 12x + 7 = 0 \]
\[ D = (-12)^2 - 4\cdot(-1)\cdot7 = 144 + 28 = 172 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{12 \pm \sqrt{172}}{-2} \]
\[ x = -6 + \sqrt{43}\quad\text{or}\quad x = -6 - \sqrt{43} \]The parabola y = -x² - 12x + 7
| x | y |
|---|---|
| -9 | 34 |
| -8 | 39 |
| -7 | 42 |
| -6 | 43 |
| -5 | 42 |
| -4 | 39 |
| -3 | 34 |
Questions
What are the solutions of -x² - 12x + 7 = 0?
The solutions of -x² - 12x + 7 = 0 are x = -6 + √43 or x = -6 - √43, that is x ≈ -12.557439 and x ≈ 0.55743852.
Does -x² - 12x + 7 = 0 factor?
Not over the integers, because the discriminant 172 is not a perfect square. Use the quadratic formula.
What is the vertex of y = -x² - 12x + 7?
(-6, 43). The parabola opens downwards, so this is the maximum.
What are the sum and product of the roots?
Sum = −b/a = -12, product = c/a = -7.