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Solve -x² - 11x - 5 = 0

The solutions of -x² - 11x - 5 = 0 are x = (-11 + √101)/2 or x = (-11 - √101)/2, that is x ≈ -10.524938 and x ≈ -0.47506219.

x² +x += 0
−x2−11x−5=0⇒x=−11+1012, −11−1012-x^2 - 11x - 5 = 0 \Rightarrow x = \frac{-11 + \sqrt{101}}{2},\ \frac{-11 - \sqrt{101}}{2}
Discriminant D = 101 · x ≈ -10.5249, -0.475062

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = -x² - 11x - 5-12-10-8-6-4-22-30-20-10102030x = -10.524938x = -0.47506219vertexy = -x² - 11x - 5
Graph of y = -x² - 11x - 5. The curve crosses the x-axis at x = -10.524938 and x = -0.47506219; the vertex is at (-5.5, 25.25).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -1, b = -11, c = -5.

    −x2−11x−5=0-x^2 - 11x - 5 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−11)2−4⋅(−1)⋅(−5)=121−20=101D = (-11)^2 - 4\cdot(-1)\cdot(-5) = 121 - 20 = 101
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=11±101−2x = \frac{-b \pm \sqrt{D}}{2a} = \frac{11 \pm \sqrt{101}}{-2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−11+1012orx=−11−1012x = \frac{-11 + \sqrt{101}}{2}\quad\text{or}\quad x = \frac{-11 - \sqrt{101}}{2}
  6. 6

    As decimals: x ≈ -10.524938 and x ≈ -0.47506219.

  7. 7

    Check numerically: for x ≈ -10.524938 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ -x^2 - 11x - 5 = 0\ \Rightarrow\ x = \frac{-11 + \sqrt{101}}{2},\ \frac{-11 - \sqrt{101}}{2} \]
\[ -x^2 - 11x - 5 = 0 \]
\[ D = (-11)^2 - 4\cdot(-1)\cdot(-5) = 121 - 20 = 101 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{11 \pm \sqrt{101}}{-2} \]
\[ x = \frac{-11 + \sqrt{101}}{2}\quad\text{or}\quad x = \frac{-11 - \sqrt{101}}{2} \]

The parabola y = -x² - 11x - 5

xy
-8.516.25
-7.521.25
-6.524.25
-5.525.25
-4.524.25
-3.521.25
-2.516.25

Questions

What are the solutions of -x² - 11x - 5 = 0?

The solutions of -x² - 11x - 5 = 0 are x = (-11 + √101)/2 or x = (-11 - √101)/2, that is x ≈ -10.524938 and x ≈ -0.47506219.

Does -x² - 11x - 5 = 0 factor?

Not over the integers, because the discriminant 101 is not a perfect square. Use the quadratic formula.

What is the vertex of y = -x² - 11x - 5?

(-11/2, 101/4). The parabola opens downwards, so this is the maximum.

What are the sum and product of the roots?

Sum = −b/a = -11, product = c/a = 5.

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    Solve -x² - 11x - 5 = 0: x = (-11 + √101)/2 or x = (-11 - √101)/2 (steps) | WordGPT