Solve -x² + 7x = 0
The solutions of -x² + 7x = 0 are x = 0 or x = 7.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -1, b = 7, c = 0.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
Method 1, factoring. The roots are rational, so the left side factors:
- 5
A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:
- 6
Method 2, The quadratic formula works for every quadratic:
- 7
Simplify to get the solutions:
- 8
Check by putting x = 0 back in: a·x² + b·x + c = -1·(0) + 7·(0) + 0 = 0 ✓
LaTeX source of the formulas on this page
\[ -x^2 + 7x = 0\ \Rightarrow\ x = 0,\ 7 \]
\[ -x^2 + 7x = 0 \]
\[ D = 7^2 - 4\cdot(-1)\cdot0 = 49 + 0 = 49 \]
\[ -\left(x\right)\left(x - 7\right) = 0 \]
\[ x = 0 \Rightarrow x = 0\qquad x - 7 = 0 \Rightarrow x = 7 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-7 \pm \sqrt{49}}{-2} \]
\[ x = 0\quad\text{or}\quad x = 7 \]The parabola y = -x² + 7x
| x | y |
|---|---|
| 0.5 | 3.25 |
| 1.5 | 8.25 |
| 2.5 | 11.25 |
| 3.5 | 12.25 |
| 4.5 | 11.25 |
| 5.5 | 8.25 |
| 6.5 | 3.25 |
Questions
What are the solutions of -x² + 7x = 0?
The solutions of -x² + 7x = 0 are x = 0 or x = 7.
Does -x² + 7x = 0 factor?
Yes: -1(x)(x-7) = 0.
What is the vertex of y = -x² + 7x?
(7/2, 49/4). The parabola opens downwards, so this is the maximum.
What are the sum and product of the roots?
Sum = −b/a = 7, product = c/a = 0.