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Solve -x² + 12x + 1 = 0

The solutions of -x² + 12x + 1 = 0 are x = 6 + √37 or x = 6 - √37, that is x ≈ -0.08276253 and x ≈ 12.082763.

x² +x += 0
−x2+12x+1=0⇒x=6+37, 6−37-x^2 + 12x + 1 = 0 \Rightarrow x = 6 + \sqrt{37},\ 6 - \sqrt{37}
Discriminant D = 148 · x ≈ -0.0827625, 12.0828

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = -x² + 12x + 1-22468101214-40-30-20-1010203040x = -0.08276253x = 12.082763vertexy = -x² + 12x + 1
Graph of y = -x² + 12x + 1. The curve crosses the x-axis at x = -0.08276253 and x = 12.082763; the vertex is at (6, 37).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -1, b = 12, c = 1.

    −x2+12x+1=0-x^2 + 12x + 1 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=122−4⋅(−1)⋅1=144+4=148D = 12^2 - 4\cdot(-1)\cdot1 = 144 + 4 = 148
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−12±148−2x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-12 \pm \sqrt{148}}{-2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=6+37orx=6−37x = 6 + \sqrt{37}\quad\text{or}\quad x = 6 - \sqrt{37}
  6. 6

    As decimals: x ≈ -0.08276253 and x ≈ 12.082763.

  7. 7

    Check numerically: for x ≈ -0.08276253 the left side is 4.2188475e-15 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ -x^2 + 12x + 1 = 0\ \Rightarrow\ x = 6 + \sqrt{37},\ 6 - \sqrt{37} \]
\[ -x^2 + 12x + 1 = 0 \]
\[ D = 12^2 - 4\cdot(-1)\cdot1 = 144 + 4 = 148 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-12 \pm \sqrt{148}}{-2} \]
\[ x = 6 + \sqrt{37}\quad\text{or}\quad x = 6 - \sqrt{37} \]

The parabola y = -x² + 12x + 1

xy
328
433
536
637
736
833
928

Questions

What are the solutions of -x² + 12x + 1 = 0?

The solutions of -x² + 12x + 1 = 0 are x = 6 + √37 or x = 6 - √37, that is x ≈ -0.08276253 and x ≈ 12.082763.

Does -x² + 12x + 1 = 0 factor?

Not over the integers, because the discriminant 148 is not a perfect square. Use the quadratic formula.

What is the vertex of y = -x² + 12x + 1?

(6, 37). The parabola opens downwards, so this is the maximum.

What are the sum and product of the roots?

Sum = −b/a = 12, product = c/a = -1.

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    Solve -x² + 12x + 1 = 0: x = 6 + √37 or x = 6 - √37 (steps) | WordGPT