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Solve -x² + 10x + 10 = 0

The solutions of -x² + 10x + 10 = 0 are x = 5 + √35 or x = 5 - √35, that is x ≈ -0.91607978 and x ≈ 10.91608.

x² +x += 0
−x2+10x+10=0⇒x=5+35, 5−35-x^2 + 10x + 10 = 0 \Rightarrow x = 5 + \sqrt{35},\ 5 - \sqrt{35}
Discriminant D = 140 · x ≈ -0.91608, 10.9161

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = -x² + 10x + 10-224681012-40-30-20-1010203040x = -0.91607978x = 10.91608vertexy = -x² + 10x + 10
Graph of y = -x² + 10x + 10. The curve crosses the x-axis at x = -0.91607978 and x = 10.91608; the vertex is at (5, 35).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -1, b = 10, c = 10.

    −x2+10x+10=0-x^2 + 10x + 10 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=102−4⋅(−1)⋅10=100+40=140D = 10^2 - 4\cdot(-1)\cdot10 = 100 + 40 = 140
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−10±140−2x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-10 \pm \sqrt{140}}{-2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=5+35orx=5−35x = 5 + \sqrt{35}\quad\text{or}\quad x = 5 - \sqrt{35}
  6. 6

    As decimals: x ≈ -0.91607978 and x ≈ 10.91608.

  7. 7

    Check numerically: for x ≈ -0.91607978 the left side is -1.7763568e-15 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ -x^2 + 10x + 10 = 0\ \Rightarrow\ x = 5 + \sqrt{35},\ 5 - \sqrt{35} \]
\[ -x^2 + 10x + 10 = 0 \]
\[ D = 10^2 - 4\cdot(-1)\cdot10 = 100 + 40 = 140 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-10 \pm \sqrt{140}}{-2} \]
\[ x = 5 + \sqrt{35}\quad\text{or}\quad x = 5 - \sqrt{35} \]

The parabola y = -x² + 10x + 10

xy
226
331
434
535
634
731
826

Questions

What are the solutions of -x² + 10x + 10 = 0?

The solutions of -x² + 10x + 10 = 0 are x = 5 + √35 or x = 5 - √35, that is x ≈ -0.91607978 and x ≈ 10.91608.

Does -x² + 10x + 10 = 0 factor?

Not over the integers, because the discriminant 140 is not a perfect square. Use the quadratic formula.

What is the vertex of y = -x² + 10x + 10?

(5, 35). The parabola opens downwards, so this is the maximum.

What are the sum and product of the roots?

Sum = −b/a = 10, product = c/a = -10.

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    Solve -x² + 10x + 10 = 0: x = 5 + √35 or x = 5 - √35 (steps) | WordGPT