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Solve 5x² - 3x + 3 = 0

5x² - 3x + 3 = 0 has no real solutions. The two complex solutions are x = (3 + √51 i)/10 and x = (3 - √51 i)/10.

x² +x += 0
5x2−3x+3=0⇒x=3+51 i10, 3−51 i10 (complex)5x^2 - 3x + 3 = 0 \Rightarrow x = \frac{3 + \sqrt{51}\, i}{10},\ \frac{3 - \sqrt{51}\, i}{10}\ \text{(complex)}
Discriminant D = -51

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 5x² - 3x + 3-3-2-1123420406080vertexy = 5x² - 3x + 3
Graph of y = 5x² - 3x + 3. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (0.3, 2.55).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = -3, c = 3.

    5x2−3x+3=05x^2 - 3x + 3 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−3)2−4⋅5⋅3=9−60=−51D = (-3)^2 - 4\cdot5\cdot3 = 9 - 60 = -51
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=3±−5110x = \frac{-b \pm \sqrt{D}}{2a} = \frac{3 \pm \sqrt{-51}}{10}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=3+51 i10orx=3−51 i10x = \frac{3 + \sqrt{51}\, i}{10}\quad\text{or}\quad x = \frac{3 - \sqrt{51}\, i}{10}
LaTeX source of the formulas on this page
\[ 5x^2 - 3x + 3 = 0\ \Rightarrow\ x = \frac{3 + \sqrt{51}\, i}{10},\ \frac{3 - \sqrt{51}\, i}{10} \]
\[ 5x^2 - 3x + 3 = 0 \]
\[ D = (-3)^2 - 4\cdot5\cdot3 = 9 - 60 = -51 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{3 \pm \sqrt{-51}}{10} \]
\[ x = \frac{3 + \sqrt{51}\, i}{10}\quad\text{or}\quad x = \frac{3 - \sqrt{51}\, i}{10} \]

The parabola y = 5x² - 3x + 3

xy
-2.747.55
-1.722.55
-0.77.55
0.32.55
1.37.55
2.322.55
3.347.55

Questions

What are the solutions of 5x² - 3x + 3 = 0?

5x² - 3x + 3 = 0 has no real solutions. The two complex solutions are x = (3 + √51 i)/10 and x = (3 - √51 i)/10.

Does 5x² - 3x + 3 = 0 factor?

Not over the integers, because the discriminant -51 is negative. Use the quadratic formula.

What is the vertex of y = 5x² - 3x + 3?

(3/10, 51/20). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 3/5, product = c/a = 3/5.

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