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Solve 5x² - 2x - 10 = 0

The solutions of 5x² - 2x - 10 = 0 are x = (1 + √51)/5 or x = (1 - √51)/5, that is x ≈ 1.6282857 and x ≈ -1.2282857.

x² +x += 0
5x2−2x−10=0⇒x=1+515, 1−5155x^2 - 2x - 10 = 0 \Rightarrow x = \frac{1 + \sqrt{51}}{5},\ \frac{1 - \sqrt{51}}{5}
Discriminant D = 204 · x ≈ 1.62829, -1.22829

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 5x² - 2x - 10-3-2-11234-20204060x = 1.6282857x = -1.2282857vertexy = 5x² - 2x - 10
Graph of y = 5x² - 2x - 10. The curve crosses the x-axis at x = 1.6282857 and x = -1.2282857; the vertex is at (0.2, -10.2).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = -2, c = -10.

    5x2−2x−10=05x^2 - 2x - 10 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−2)2−4⋅5⋅(−10)=4+200=204D = (-2)^2 - 4\cdot5\cdot(-10) = 4 + 200 = 204
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=2±20410x = \frac{-b \pm \sqrt{D}}{2a} = \frac{2 \pm \sqrt{204}}{10}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=1+515orx=1−515x = \frac{1 + \sqrt{51}}{5}\quad\text{or}\quad x = \frac{1 - \sqrt{51}}{5}
  6. 6

    As decimals: x ≈ 1.6282857 and x ≈ -1.2282857.

  7. 7

    Check numerically: for x ≈ 1.6282857 the left side is 1.7763568e-15 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ 5x^2 - 2x - 10 = 0\ \Rightarrow\ x = \frac{1 + \sqrt{51}}{5},\ \frac{1 - \sqrt{51}}{5} \]
\[ 5x^2 - 2x - 10 = 0 \]
\[ D = (-2)^2 - 4\cdot5\cdot(-10) = 4 + 200 = 204 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{2 \pm \sqrt{204}}{10} \]
\[ x = \frac{1 + \sqrt{51}}{5}\quad\text{or}\quad x = \frac{1 - \sqrt{51}}{5} \]

The parabola y = 5x² - 2x - 10

xy
-2.834.8
-1.89.8
-0.8-5.2
0.2-10.2
1.2-5.2
2.29.8
3.234.8

Questions

What are the solutions of 5x² - 2x - 10 = 0?

The solutions of 5x² - 2x - 10 = 0 are x = (1 + √51)/5 or x = (1 - √51)/5, that is x ≈ 1.6282857 and x ≈ -1.2282857.

Does 5x² - 2x - 10 = 0 factor?

Not over the integers, because the discriminant 204 is not a perfect square. Use the quadratic formula.

What is the vertex of y = 5x² - 2x - 10?

(1/5, -51/5). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 2/5, product = c/a = -2.

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    Solve 5x² - 2x - 10 = 0: x = (1 + √51)/5 or x = (1 - √51)/5 (steps) | WordGPT