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Solve 5x² - 2x + 5 = 0

5x² - 2x + 5 = 0 has no real solutions. The two complex solutions are x = (1 + 2√6 i)/5 and x = (1 - 2√6 i)/5.

x² +x += 0
5x2−2x+5=0⇒x=1+26 i5, 1−26 i5 (complex)5x^2 - 2x + 5 = 0 \Rightarrow x = \frac{1 + 2\sqrt{6}\, i}{5},\ \frac{1 - 2\sqrt{6}\, i}{5}\ \text{(complex)}
Discriminant D = -96

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 5x² - 2x + 5-3-2-1123420406080vertexy = 5x² - 2x + 5
Graph of y = 5x² - 2x + 5. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (0.2, 4.8).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = -2, c = 5.

    5x2−2x+5=05x^2 - 2x + 5 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−2)2−4⋅5⋅5=4−100=−96D = (-2)^2 - 4\cdot5\cdot5 = 4 - 100 = -96
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=2±−9610x = \frac{-b \pm \sqrt{D}}{2a} = \frac{2 \pm \sqrt{-96}}{10}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=1+26 i5orx=1−26 i5x = \frac{1 + 2\sqrt{6}\, i}{5}\quad\text{or}\quad x = \frac{1 - 2\sqrt{6}\, i}{5}
LaTeX source of the formulas on this page
\[ 5x^2 - 2x + 5 = 0\ \Rightarrow\ x = \frac{1 + 2\sqrt{6}\, i}{5},\ \frac{1 - 2\sqrt{6}\, i}{5} \]
\[ 5x^2 - 2x + 5 = 0 \]
\[ D = (-2)^2 - 4\cdot5\cdot5 = 4 - 100 = -96 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{2 \pm \sqrt{-96}}{10} \]
\[ x = \frac{1 + 2\sqrt{6}\, i}{5}\quad\text{or}\quad x = \frac{1 - 2\sqrt{6}\, i}{5} \]

The parabola y = 5x² - 2x + 5

xy
-2.849.8
-1.824.8
-0.89.8
0.24.8
1.29.8
2.224.8
3.249.8

Questions

What are the solutions of 5x² - 2x + 5 = 0?

5x² - 2x + 5 = 0 has no real solutions. The two complex solutions are x = (1 + 2√6 i)/5 and x = (1 - 2√6 i)/5.

Does 5x² - 2x + 5 = 0 factor?

Not over the integers, because the discriminant -96 is negative. Use the quadratic formula.

What is the vertex of y = 5x² - 2x + 5?

(1/5, 24/5). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 2/5, product = c/a = 1.

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