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Solve 5x² - x - 7 = 0

The solutions of 5x² - x - 7 = 0 are x = (1 + √141)/10 or x = (1 - √141)/10, that is x ≈ 1.2874342 and x ≈ -1.0874342.

x² +x += 0
5x2−x−7=0⇒x=1+14110, 1−141105x^2 - x - 7 = 0 \Rightarrow x = \frac{1 + \sqrt{141}}{10},\ \frac{1 - \sqrt{141}}{10}
Discriminant D = 141 · x ≈ 1.28743, -1.08743

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 5x² - x - 7-3-2-1123-10102030405060x = 1.2874342x = -1.0874342vertexy = 5x² - x - 7
Graph of y = 5x² - x - 7. The curve crosses the x-axis at x = 1.2874342 and x = -1.0874342; the vertex is at (0.1, -7.05).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = -1, c = -7.

    5x2−x−7=05x^2 - x - 7 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−1)2−4⋅5⋅(−7)=1+140=141D = (-1)^2 - 4\cdot5\cdot(-7) = 1 + 140 = 141
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=1±14110x = \frac{-b \pm \sqrt{D}}{2a} = \frac{1 \pm \sqrt{141}}{10}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=1+14110orx=1−14110x = \frac{1 + \sqrt{141}}{10}\quad\text{or}\quad x = \frac{1 - \sqrt{141}}{10}
  6. 6

    As decimals: x ≈ 1.2874342 and x ≈ -1.0874342.

  7. 7

    Check numerically: for x ≈ 1.2874342 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ 5x^2 - x - 7 = 0\ \Rightarrow\ x = \frac{1 + \sqrt{141}}{10},\ \frac{1 - \sqrt{141}}{10} \]
\[ 5x^2 - x - 7 = 0 \]
\[ D = (-1)^2 - 4\cdot5\cdot(-7) = 1 + 140 = 141 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{1 \pm \sqrt{141}}{10} \]
\[ x = \frac{1 + \sqrt{141}}{10}\quad\text{or}\quad x = \frac{1 - \sqrt{141}}{10} \]

The parabola y = 5x² - x - 7

xy
-2.937.95
-1.912.95
-0.9-2.05
0.1-7.05
1.1-2.05
2.112.95
3.137.95

Questions

What are the solutions of 5x² - x - 7 = 0?

The solutions of 5x² - x - 7 = 0 are x = (1 + √141)/10 or x = (1 - √141)/10, that is x ≈ 1.2874342 and x ≈ -1.0874342.

Does 5x² - x - 7 = 0 factor?

Not over the integers, because the discriminant 141 is not a perfect square. Use the quadratic formula.

What is the vertex of y = 5x² - x - 7?

(1/10, -141/20). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 1/5, product = c/a = -7/5.

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    Solve 5x² - x - 7 = 0: x = (1 + √141)/10 or x = (1 - √141)/10 (steps) | WordGPT