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Solve 5x² - 11x + 9 = 0

5x² - 11x + 9 = 0 has no real solutions. The two complex solutions are x = (11 + √59 i)/10 and x = (11 - √59 i)/10.

x² +x += 0
5x2−11x+9=0⇒x=11+59 i10, 11−59 i10 (complex)5x^2 - 11x + 9 = 0 \Rightarrow x = \frac{11 + \sqrt{59}\, i}{10},\ \frac{11 - \sqrt{59}\, i}{10}\ \text{(complex)}
Discriminant D = -59

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 5x² - 11x + 9-2-11234520406080vertexy = 5x² - 11x + 9
Graph of y = 5x² - 11x + 9. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (1.1, 2.95).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = -11, c = 9.

    5x2−11x+9=05x^2 - 11x + 9 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−11)2−4⋅5⋅9=121−180=−59D = (-11)^2 - 4\cdot5\cdot9 = 121 - 180 = -59
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=11±−5910x = \frac{-b \pm \sqrt{D}}{2a} = \frac{11 \pm \sqrt{-59}}{10}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=11+59 i10orx=11−59 i10x = \frac{11 + \sqrt{59}\, i}{10}\quad\text{or}\quad x = \frac{11 - \sqrt{59}\, i}{10}
LaTeX source of the formulas on this page
\[ 5x^2 - 11x + 9 = 0\ \Rightarrow\ x = \frac{11 + \sqrt{59}\, i}{10},\ \frac{11 - \sqrt{59}\, i}{10} \]
\[ 5x^2 - 11x + 9 = 0 \]
\[ D = (-11)^2 - 4\cdot5\cdot9 = 121 - 180 = -59 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{11 \pm \sqrt{-59}}{10} \]
\[ x = \frac{11 + \sqrt{59}\, i}{10}\quad\text{or}\quad x = \frac{11 - \sqrt{59}\, i}{10} \]

The parabola y = 5x² - 11x + 9

xy
-1.947.95
-0.922.95
0.17.95
1.12.95
2.17.95
3.122.95
4.147.95

Questions

What are the solutions of 5x² - 11x + 9 = 0?

5x² - 11x + 9 = 0 has no real solutions. The two complex solutions are x = (11 + √59 i)/10 and x = (11 - √59 i)/10.

Does 5x² - 11x + 9 = 0 factor?

Not over the integers, because the discriminant -59 is negative. Use the quadratic formula.

What is the vertex of y = 5x² - 11x + 9?

(11/10, 59/20). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 11/5, product = c/a = 9/5.

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