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Solve 5x² - 10x - 5 = 0

The solutions of 5x² - 10x - 5 = 0 are x = 1 + √2 or x = 1 - √2, that is x ≈ 2.4142136 and x ≈ -0.41421356.

x² +x += 0
5x2−10x−5=0⇒x=1+2, 1−25x^2 - 10x - 5 = 0 \Rightarrow x = 1 + \sqrt{2},\ 1 - \sqrt{2}
Discriminant D = 200 · x ≈ 2.41421, -0.414214

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 5x² - 10x - 5-2-11234-20204060x = 2.4142136x = -0.41421356vertexy = 5x² - 10x - 5
Graph of y = 5x² - 10x - 5. The curve crosses the x-axis at x = 2.4142136 and x = -0.41421356; the vertex is at (1, -10).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = -10, c = -5.

    5x2−10x−5=05x^2 - 10x - 5 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−10)2−4⋅5⋅(−5)=100+100=200D = (-10)^2 - 4\cdot5\cdot(-5) = 100 + 100 = 200
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=10±20010x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{200}}{10}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=1+2orx=1−2x = 1 + \sqrt{2}\quad\text{or}\quad x = 1 - \sqrt{2}
  6. 6

    As decimals: x ≈ 2.4142136 and x ≈ -0.41421356.

  7. 7

    Check numerically: for x ≈ 2.4142136 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ 5x^2 - 10x - 5 = 0\ \Rightarrow\ x = 1 + \sqrt{2},\ 1 - \sqrt{2} \]
\[ 5x^2 - 10x - 5 = 0 \]
\[ D = (-10)^2 - 4\cdot5\cdot(-5) = 100 + 100 = 200 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{200}}{10} \]
\[ x = 1 + \sqrt{2}\quad\text{or}\quad x = 1 - \sqrt{2} \]

The parabola y = 5x² - 10x - 5

xy
-235
-110
0-5
1-10
2-5
310
435

Questions

What are the solutions of 5x² - 10x - 5 = 0?

The solutions of 5x² - 10x - 5 = 0 are x = 1 + √2 or x = 1 - √2, that is x ≈ 2.4142136 and x ≈ -0.41421356.

Does 5x² - 10x - 5 = 0 factor?

Not over the integers, because the discriminant 200 is not a perfect square. Use the quadratic formula.

What is the vertex of y = 5x² - 10x - 5?

(1, -10). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 2, product = c/a = -1.

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