Solve 5x² - 10x + 1 = 0
The solutions of 5x² - 10x + 1 = 0 are x = (5 + 2√5)/5 or x = (5 - 2√5)/5, that is x ≈ 1.8944272 and x ≈ 0.10557281.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = -10, c = 1.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
The quadratic formula works for every quadratic:
- 5
Simplify (pull the square out of the root) to get the solutions:
- 6
As decimals: x ≈ 1.8944272 and x ≈ 0.10557281.
- 7
Check numerically: for x ≈ 1.8944272 the left side is 0 (zero up to rounding) ✓
LaTeX source of the formulas on this page
\[ 5x^2 - 10x + 1 = 0\ \Rightarrow\ x = \frac{5 + 2\sqrt{5}}{5},\ \frac{5 - 2\sqrt{5}}{5} \]
\[ 5x^2 - 10x + 1 = 0 \]
\[ D = (-10)^2 - 4\cdot5\cdot1 = 100 - 20 = 80 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{80}}{10} \]
\[ x = \frac{5 + 2\sqrt{5}}{5}\quad\text{or}\quad x = \frac{5 - 2\sqrt{5}}{5} \]The parabola y = 5x² - 10x + 1
| x | y |
|---|---|
| -2 | 41 |
| -1 | 16 |
| 0 | 1 |
| 1 | -4 |
| 2 | 1 |
| 3 | 16 |
| 4 | 41 |
Questions
What are the solutions of 5x² - 10x + 1 = 0?
The solutions of 5x² - 10x + 1 = 0 are x = (5 + 2√5)/5 or x = (5 - 2√5)/5, that is x ≈ 1.8944272 and x ≈ 0.10557281.
Does 5x² - 10x + 1 = 0 factor?
Not over the integers, because the discriminant 80 is not a perfect square. Use the quadratic formula.
What is the vertex of y = 5x² - 10x + 1?
(1, -4). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = 2, product = c/a = 1/5.