Solve 5x² + 9x = 0
The solutions of 5x² + 9x = 0 are x = 0 or x = -9/5.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = 9, c = 0.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
Method 1, factoring. The roots are rational, so the left side factors:
- 5
A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:
- 6
Method 2, The quadratic formula works for every quadratic:
- 7
Simplify to get the solutions:
- 8
Check by putting x = 0 back in: a·x² + b·x + c = 5·(0) + 9·(0) + 0 = 0 ✓
LaTeX source of the formulas on this page
\[ 5x^2 + 9x = 0\ \Rightarrow\ x = 0,\ -\frac{9}{5} \]
\[ 5x^2 + 9x = 0 \]
\[ D = 9^2 - 4\cdot5\cdot0 = 81 + 0 = 81 \]
\[ \left(x\right)\left(5x + 9\right) = 0 \]
\[ x = 0 \Rightarrow x = 0\qquad 5x + 9 = 0 \Rightarrow x = -\frac{9}{5} \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-9 \pm \sqrt{81}}{10} \]
\[ x = 0\quad\text{or}\quad x = -\frac{9}{5} \]The parabola y = 5x² + 9x
| x | y |
|---|---|
| -3.9 | 40.95 |
| -2.9 | 15.95 |
| -1.9 | 0.95 |
| -0.9 | -4.05 |
| 0.1 | 0.95 |
| 1.1 | 15.95 |
| 2.1 | 40.95 |
Questions
What are the solutions of 5x² + 9x = 0?
The solutions of 5x² + 9x = 0 are x = 0 or x = -9/5.
Does 5x² + 9x = 0 factor?
Yes: (x)(5x+9) = 0.
What is the vertex of y = 5x² + 9x?
(-9/10, -81/20). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = -9/5, product = c/a = 0.