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Solve 5x² + 8x + 8 = 0

5x² + 8x + 8 = 0 has no real solutions. The two complex solutions are x = (-4 + 2√6 i)/5 and x = (-4 - 2√6 i)/5.

x² +x += 0
5x2+8x+8=0⇒x=−4+26 i5, −4−26 i5 (complex)5x^2 + 8x + 8 = 0 \Rightarrow x = \frac{-4 + 2\sqrt{6}\, i}{5},\ \frac{-4 - 2\sqrt{6}\, i}{5}\ \text{(complex)}
Discriminant D = -96

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 5x² + 8x + 8-4-3-2-112320406080vertexy = 5x² + 8x + 8
Graph of y = 5x² + 8x + 8. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (-0.8, 4.8).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = 8, c = 8.

    5x2+8x+8=05x^2 + 8x + 8 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=82−4⋅5⋅8=64−160=−96D = 8^2 - 4\cdot5\cdot8 = 64 - 160 = -96
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−8±−9610x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{-96}}{10}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−4+26 i5orx=−4−26 i5x = \frac{-4 + 2\sqrt{6}\, i}{5}\quad\text{or}\quad x = \frac{-4 - 2\sqrt{6}\, i}{5}
LaTeX source of the formulas on this page
\[ 5x^2 + 8x + 8 = 0\ \Rightarrow\ x = \frac{-4 + 2\sqrt{6}\, i}{5},\ \frac{-4 - 2\sqrt{6}\, i}{5} \]
\[ 5x^2 + 8x + 8 = 0 \]
\[ D = 8^2 - 4\cdot5\cdot8 = 64 - 160 = -96 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{-96}}{10} \]
\[ x = \frac{-4 + 2\sqrt{6}\, i}{5}\quad\text{or}\quad x = \frac{-4 - 2\sqrt{6}\, i}{5} \]

The parabola y = 5x² + 8x + 8

xy
-3.849.8
-2.824.8
-1.89.8
-0.84.8
0.29.8
1.224.8
2.249.8

Questions

What are the solutions of 5x² + 8x + 8 = 0?

5x² + 8x + 8 = 0 has no real solutions. The two complex solutions are x = (-4 + 2√6 i)/5 and x = (-4 - 2√6 i)/5.

Does 5x² + 8x + 8 = 0 factor?

Not over the integers, because the discriminant -96 is negative. Use the quadratic formula.

What is the vertex of y = 5x² + 8x + 8?

(-4/5, 24/5). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -8/5, product = c/a = 8/5.

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