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Solve 5x² + 5x + 3 = 0

5x² + 5x + 3 = 0 has no real solutions. The two complex solutions are x = (-5 + √35 i)/10 and x = (-5 - √35 i)/10.

x² +x += 0
5x2+5x+3=0⇒x=−5+35 i10, −5−35 i10 (complex)5x^2 + 5x + 3 = 0 \Rightarrow x = \frac{-5 + \sqrt{35}\, i}{10},\ \frac{-5 - \sqrt{35}\, i}{10}\ \text{(complex)}
Discriminant D = -35

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 5x² + 5x + 3-4-3-2-112320406080vertexy = 5x² + 5x + 3
Graph of y = 5x² + 5x + 3. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (-0.5, 1.75).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = 5, c = 3.

    5x2+5x+3=05x^2 + 5x + 3 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=52−4⋅5⋅3=25−60=−35D = 5^2 - 4\cdot5\cdot3 = 25 - 60 = -35
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−5±−3510x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-5 \pm \sqrt{-35}}{10}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−5+35 i10orx=−5−35 i10x = \frac{-5 + \sqrt{35}\, i}{10}\quad\text{or}\quad x = \frac{-5 - \sqrt{35}\, i}{10}
LaTeX source of the formulas on this page
\[ 5x^2 + 5x + 3 = 0\ \Rightarrow\ x = \frac{-5 + \sqrt{35}\, i}{10},\ \frac{-5 - \sqrt{35}\, i}{10} \]
\[ 5x^2 + 5x + 3 = 0 \]
\[ D = 5^2 - 4\cdot5\cdot3 = 25 - 60 = -35 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-5 \pm \sqrt{-35}}{10} \]
\[ x = \frac{-5 + \sqrt{35}\, i}{10}\quad\text{or}\quad x = \frac{-5 - \sqrt{35}\, i}{10} \]

The parabola y = 5x² + 5x + 3

xy
-3.546.75
-2.521.75
-1.56.75
-0.51.75
0.56.75
1.521.75
2.546.75

Questions

What are the solutions of 5x² + 5x + 3 = 0?

5x² + 5x + 3 = 0 has no real solutions. The two complex solutions are x = (-5 + √35 i)/10 and x = (-5 - √35 i)/10.

Does 5x² + 5x + 3 = 0 factor?

Not over the integers, because the discriminant -35 is negative. Use the quadratic formula.

What is the vertex of y = 5x² + 5x + 3?

(-1/2, 7/4). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -1, product = c/a = 3/5.

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