Solve 5x² + 12x - 9 = 0
The solutions of 5x² + 12x - 9 = 0 are x = 3/5 or x = -3.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = 12, c = -9.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
Method 1, factoring. The roots are rational, so the left side factors:
- 5
A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:
- 6
Method 2, The quadratic formula works for every quadratic:
- 7
Simplify to get the solutions:
- 8
Check by putting x = 3/5 back in: a·x² + b·x + c = 5·(9/25) + 12·(3/5) + (-9) = 0 ✓
LaTeX source of the formulas on this page
\[ 5x^2 + 12x - 9 = 0\ \Rightarrow\ x = \frac{3}{5},\ -3 \]
\[ 5x^2 + 12x - 9 = 0 \]
\[ D = 12^2 - 4\cdot5\cdot(-9) = 144 + 180 = 324 \]
\[ \left(5x - 3\right)\left(x + 3\right) = 0 \]
\[ 5x - 3 = 0 \Rightarrow x = \frac{3}{5}\qquad x + 3 = 0 \Rightarrow x = -3 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-12 \pm \sqrt{324}}{10} \]
\[ x = \frac{3}{5}\quad\text{or}\quad x = -3 \]The parabola y = 5x² + 12x - 9
| x | y |
|---|---|
| -4.2 | 28.8 |
| -3.2 | 3.8 |
| -2.2 | -11.2 |
| -1.2 | -16.2 |
| -0.2 | -11.2 |
| 0.8 | 3.8 |
| 1.8 | 28.8 |
Questions
What are the solutions of 5x² + 12x - 9 = 0?
The solutions of 5x² + 12x - 9 = 0 are x = 3/5 or x = -3.
Does 5x² + 12x - 9 = 0 factor?
Yes: (5x-3)(x+3) = 0.
What is the vertex of y = 5x² + 12x - 9?
(-6/5, -81/5). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = -12/5, product = c/a = -9/5.