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Solve 5x² + 11x - 12 = 0

The solutions of 5x² + 11x - 12 = 0 are x = 4/5 or x = -3.

x² +x += 0
5x2+11x−12=0⇒x=45, −35x^2 + 11x - 12 = 0 \Rightarrow x = \frac{4}{5},\ -3
Discriminant D = 361 · x ≈ 0.8, -3

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = 5x² + 11x - 12-5-4-3-2-1123-2020406080x = 0.8x = -3vertexy = 5x² + 11x - 12
Graph of y = 5x² + 11x - 12. The curve crosses the x-axis at x = 0.8 and x = -3; the vertex is at (-1.1, -18.05).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = 11, c = -12.

    5x2+11x−12=05x^2 + 11x - 12 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=112−4⋅5⋅(−12)=121+240=361D = 11^2 - 4\cdot5\cdot(-12) = 121 + 240 = 361
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    Method 1, factoring. The roots are rational, so the left side factors:

    (5x−4)(x+3)=0\left(5x - 4\right)\left(x + 3\right) = 0
  5. 5

    A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:

    5x−4=0⇒x=45x+3=0⇒x=−35x - 4 = 0 \Rightarrow x = \frac{4}{5}\qquad x + 3 = 0 \Rightarrow x = -3
  6. 6

    Method 2, The quadratic formula works for every quadratic:

    x=−b±D2a=−11±36110x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-11 \pm \sqrt{361}}{10}
  7. 7

    Simplify to get the solutions:

    x=45orx=−3x = \frac{4}{5}\quad\text{or}\quad x = -3
  8. 8

    Check by putting x = 4/5 back in: a·x² + b·x + c = 5·(16/25) + 11·(4/5) + (-12) = 0 ✓

LaTeX source of the formulas on this page
\[ 5x^2 + 11x - 12 = 0\ \Rightarrow\ x = \frac{4}{5},\ -3 \]
\[ 5x^2 + 11x - 12 = 0 \]
\[ D = 11^2 - 4\cdot5\cdot(-12) = 121 + 240 = 361 \]
\[ \left(5x - 4\right)\left(x + 3\right) = 0 \]
\[ 5x - 4 = 0 \Rightarrow x = \frac{4}{5}\qquad x + 3 = 0 \Rightarrow x = -3 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-11 \pm \sqrt{361}}{10} \]
\[ x = \frac{4}{5}\quad\text{or}\quad x = -3 \]

The parabola y = 5x² + 11x - 12

xy
-4.126.95
-3.11.95
-2.1-13.05
-1.1-18.05
-0.1-13.05
0.91.95
1.926.95

Questions

What are the solutions of 5x² + 11x - 12 = 0?

The solutions of 5x² + 11x - 12 = 0 are x = 4/5 or x = -3.

Does 5x² + 11x - 12 = 0 factor?

Yes: (5x-4)(x+3) = 0.

What is the vertex of y = 5x² + 11x - 12?

(-11/10, -361/20). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -11/5, product = c/a = -12/5.

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