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Solve 5x² - 3 = 0

The solutions of 5x² - 3 = 0 are x = (√15)/5 or x = (-√15)/5, that is x ≈ 0.77459667 and x ≈ -0.77459667.

x² +x += 0
5x2−3=0⇒x=155, −1555x^2 - 3 = 0 \Rightarrow x = \frac{\sqrt{15}}{5},\ \frac{-\sqrt{15}}{5}
Discriminant D = 60 · x ≈ 0.774597, -0.774597

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 5x² - 3-3-2-1123-101020304050x = 0.77459667x = -0.77459667vertexy = 5x² - 3
Graph of y = 5x² - 3. The curve crosses the x-axis at x = 0.77459667 and x = -0.77459667; the vertex is at (0, -3).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = 0, c = -3.

    5x2−3=05x^2 - 3 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=02−4⋅5⋅(−3)=0+60=60D = 0^2 - 4\cdot5\cdot(-3) = 0 + 60 = 60
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=0±6010x = \frac{-b \pm \sqrt{D}}{2a} = \frac{0 \pm \sqrt{60}}{10}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=155orx=−155x = \frac{\sqrt{15}}{5}\quad\text{or}\quad x = \frac{-\sqrt{15}}{5}
  6. 6

    As decimals: x ≈ 0.77459667 and x ≈ -0.77459667.

  7. 7

    Check numerically: for x ≈ 0.77459667 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ 5x^2 - 3 = 0\ \Rightarrow\ x = \frac{\sqrt{15}}{5},\ \frac{-\sqrt{15}}{5} \]
\[ 5x^2 - 3 = 0 \]
\[ D = 0^2 - 4\cdot5\cdot(-3) = 0 + 60 = 60 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{0 \pm \sqrt{60}}{10} \]
\[ x = \frac{\sqrt{15}}{5}\quad\text{or}\quad x = \frac{-\sqrt{15}}{5} \]

The parabola y = 5x² - 3

xy
-342
-217
-12
0-3
12
217
342

Questions

What are the solutions of 5x² - 3 = 0?

The solutions of 5x² - 3 = 0 are x = (√15)/5 or x = (-√15)/5, that is x ≈ 0.77459667 and x ≈ -0.77459667.

Does 5x² - 3 = 0 factor?

Not over the integers, because the discriminant 60 is not a perfect square. Use the quadratic formula.

What is the vertex of y = 5x² - 3?

(0, -3). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 0, product = c/a = -3/5.

Similar equations

    Solve 5x² - 3 = 0: x = (√15)/5 or x = (-√15)/5 (steps) | WordGPT