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Solve 4x² - 9x + 7 = 0

4x² - 9x + 7 = 0 has no real solutions. The two complex solutions are x = (9 + √31 i)/8 and x = (9 - √31 i)/8.

x² +x += 0
4x2−9x+7=0⇒x=9+31 i8, 9−31 i8 (complex)4x^2 - 9x + 7 = 0 \Rightarrow x = \frac{9 + \sqrt{31}\, i}{8},\ \frac{9 - \sqrt{31}\, i}{8}\ \text{(complex)}
Discriminant D = -31

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 4x² - 9x + 7-2-11234510203040506070vertexy = 4x² - 9x + 7
Graph of y = 4x² - 9x + 7. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (1.125, 1.9375).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 4, b = -9, c = 7.

    4x2−9x+7=04x^2 - 9x + 7 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−9)2−4⋅4⋅7=81−112=−31D = (-9)^2 - 4\cdot4\cdot7 = 81 - 112 = -31
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=9±−318x = \frac{-b \pm \sqrt{D}}{2a} = \frac{9 \pm \sqrt{-31}}{8}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=9+31 i8orx=9−31 i8x = \frac{9 + \sqrt{31}\, i}{8}\quad\text{or}\quad x = \frac{9 - \sqrt{31}\, i}{8}
LaTeX source of the formulas on this page
\[ 4x^2 - 9x + 7 = 0\ \Rightarrow\ x = \frac{9 + \sqrt{31}\, i}{8},\ \frac{9 - \sqrt{31}\, i}{8} \]
\[ 4x^2 - 9x + 7 = 0 \]
\[ D = (-9)^2 - 4\cdot4\cdot7 = 81 - 112 = -31 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{9 \pm \sqrt{-31}}{8} \]
\[ x = \frac{9 + \sqrt{31}\, i}{8}\quad\text{or}\quad x = \frac{9 - \sqrt{31}\, i}{8} \]

The parabola y = 4x² - 9x + 7

xy
-1.87537.9375
-0.87517.9375
0.1255.9375
1.1251.9375
2.1255.9375
3.12517.9375
4.12537.9375

Questions

What are the solutions of 4x² - 9x + 7 = 0?

4x² - 9x + 7 = 0 has no real solutions. The two complex solutions are x = (9 + √31 i)/8 and x = (9 - √31 i)/8.

Does 4x² - 9x + 7 = 0 factor?

Not over the integers, because the discriminant -31 is negative. Use the quadratic formula.

What is the vertex of y = 4x² - 9x + 7?

(9/8, 31/16). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 9/4, product = c/a = 7/4.

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