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Solve 4x² - x - 9 = 0

The solutions of 4x² - x - 9 = 0 are x = (1 + √145)/8 or x = (1 - √145)/8, that is x ≈ 1.6301993 and x ≈ -1.3801993.

x² +x += 0
4x2−x−9=0⇒x=1+1458, 1−14584x^2 - x - 9 = 0 \Rightarrow x = \frac{1 + \sqrt{145}}{8},\ \frac{1 - \sqrt{145}}{8}
Discriminant D = 145 · x ≈ 1.6302, -1.3802

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 4x² - x - 9-3-2-11234-10102030405060x = 1.6301993x = -1.3801993vertexy = 4x² - x - 9
Graph of y = 4x² - x - 9. The curve crosses the x-axis at x = 1.6301993 and x = -1.3801993; the vertex is at (0.125, -9.0625).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 4, b = -1, c = -9.

    4x2−x−9=04x^2 - x - 9 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−1)2−4⋅4⋅(−9)=1+144=145D = (-1)^2 - 4\cdot4\cdot(-9) = 1 + 144 = 145
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=1±1458x = \frac{-b \pm \sqrt{D}}{2a} = \frac{1 \pm \sqrt{145}}{8}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=1+1458orx=1−1458x = \frac{1 + \sqrt{145}}{8}\quad\text{or}\quad x = \frac{1 - \sqrt{145}}{8}
  6. 6

    As decimals: x ≈ 1.6301993 and x ≈ -1.3801993.

  7. 7

    Check numerically: for x ≈ 1.6301993 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ 4x^2 - x - 9 = 0\ \Rightarrow\ x = \frac{1 + \sqrt{145}}{8},\ \frac{1 - \sqrt{145}}{8} \]
\[ 4x^2 - x - 9 = 0 \]
\[ D = (-1)^2 - 4\cdot4\cdot(-9) = 1 + 144 = 145 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{1 \pm \sqrt{145}}{8} \]
\[ x = \frac{1 + \sqrt{145}}{8}\quad\text{or}\quad x = \frac{1 - \sqrt{145}}{8} \]

The parabola y = 4x² - x - 9

xy
-2.87526.9375
-1.8756.9375
-0.875-5.0625
0.125-9.0625
1.125-5.0625
2.1256.9375
3.12526.9375

Questions

What are the solutions of 4x² - x - 9 = 0?

The solutions of 4x² - x - 9 = 0 are x = (1 + √145)/8 or x = (1 - √145)/8, that is x ≈ 1.6301993 and x ≈ -1.3801993.

Does 4x² - x - 9 = 0 factor?

Not over the integers, because the discriminant 145 is not a perfect square. Use the quadratic formula.

What is the vertex of y = 4x² - x - 9?

(1/8, -145/16). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 1/4, product = c/a = -9/4.

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