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Solve 4x² - 10x + 3 = 0

The solutions of 4x² - 10x + 3 = 0 are x = (5 + √13)/4 or x = (5 - √13)/4, that is x ≈ 2.1513878 and x ≈ 0.34861218.

x² +x += 0
4x2−10x+3=0⇒x=5+134, 5−1344x^2 - 10x + 3 = 0 \Rightarrow x = \frac{5 + \sqrt{13}}{4},\ \frac{5 - \sqrt{13}}{4}
Discriminant D = 52 · x ≈ 2.15139, 0.348612

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 4x² - 10x + 3-2-1123410203040x = 2.1513878x = 0.34861218vertexy = 4x² - 10x + 3
Graph of y = 4x² - 10x + 3. The curve crosses the x-axis at x = 2.1513878 and x = 0.34861218; the vertex is at (1.25, -3.25).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 4, b = -10, c = 3.

    4x2−10x+3=04x^2 - 10x + 3 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−10)2−4⋅4⋅3=100−48=52D = (-10)^2 - 4\cdot4\cdot3 = 100 - 48 = 52
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=10±528x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{52}}{8}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=5+134orx=5−134x = \frac{5 + \sqrt{13}}{4}\quad\text{or}\quad x = \frac{5 - \sqrt{13}}{4}
  6. 6

    As decimals: x ≈ 2.1513878 and x ≈ 0.34861218.

  7. 7

    Check numerically: for x ≈ 2.1513878 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ 4x^2 - 10x + 3 = 0\ \Rightarrow\ x = \frac{5 + \sqrt{13}}{4},\ \frac{5 - \sqrt{13}}{4} \]
\[ 4x^2 - 10x + 3 = 0 \]
\[ D = (-10)^2 - 4\cdot4\cdot3 = 100 - 48 = 52 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{52}}{8} \]
\[ x = \frac{5 + \sqrt{13}}{4}\quad\text{or}\quad x = \frac{5 - \sqrt{13}}{4} \]

The parabola y = 4x² - 10x + 3

xy
-1.7532.75
-0.7512.75
0.250.75
1.25-3.25
2.250.75
3.2512.75
4.2532.75

Questions

What are the solutions of 4x² - 10x + 3 = 0?

The solutions of 4x² - 10x + 3 = 0 are x = (5 + √13)/4 or x = (5 - √13)/4, that is x ≈ 2.1513878 and x ≈ 0.34861218.

Does 4x² - 10x + 3 = 0 factor?

Not over the integers, because the discriminant 52 is not a perfect square. Use the quadratic formula.

What is the vertex of y = 4x² - 10x + 3?

(5/4, -13/4). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 5/2, product = c/a = 3/4.

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    Solve 4x² - 10x + 3 = 0: x = (5 + √13)/4 or x = (5 - √13)/4 (steps) | WordGPT