Solve 4x² + 9x + 6 = 0
4x² + 9x + 6 = 0 has no real solutions. The two complex solutions are x = (-9 + √15 i)/8 and x = (-9 - √15 i)/8.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 4, b = 9, c = 6.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is negative, so there are no real solutions; the two solutions are complex numbers.
- 4
The quadratic formula works for every quadratic:
- 5
Simplify (pull the square out of the root) to get the solutions:
LaTeX source of the formulas on this page
\[ 4x^2 + 9x + 6 = 0\ \Rightarrow\ x = \frac{-9 + \sqrt{15}\, i}{8},\ \frac{-9 - \sqrt{15}\, i}{8} \]
\[ 4x^2 + 9x + 6 = 0 \]
\[ D = 9^2 - 4\cdot4\cdot6 = 81 - 96 = -15 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-9 \pm \sqrt{-15}}{8} \]
\[ x = \frac{-9 + \sqrt{15}\, i}{8}\quad\text{or}\quad x = \frac{-9 - \sqrt{15}\, i}{8} \]The parabola y = 4x² + 9x + 6
| x | y |
|---|---|
| -4.125 | 36.9375 |
| -3.125 | 16.9375 |
| -2.125 | 4.9375 |
| -1.125 | 0.9375 |
| -0.125 | 4.9375 |
| 0.875 | 16.9375 |
| 1.875 | 36.9375 |
Questions
What are the solutions of 4x² + 9x + 6 = 0?
4x² + 9x + 6 = 0 has no real solutions. The two complex solutions are x = (-9 + √15 i)/8 and x = (-9 - √15 i)/8.
Does 4x² + 9x + 6 = 0 factor?
Not over the integers, because the discriminant -15 is negative. Use the quadratic formula.
What is the vertex of y = 4x² + 9x + 6?
(-9/8, 15/16). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = -9/4, product = c/a = 3/2.