Solve 4x² + 6x + 7 = 0
4x² + 6x + 7 = 0 has no real solutions. The two complex solutions are x = (-3 + √19 i)/4 and x = (-3 - √19 i)/4.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 4, b = 6, c = 7.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is negative, so there are no real solutions; the two solutions are complex numbers.
- 4
The quadratic formula works for every quadratic:
- 5
Simplify (pull the square out of the root) to get the solutions:
LaTeX source of the formulas on this page
\[ 4x^2 + 6x + 7 = 0\ \Rightarrow\ x = \frac{-3 + \sqrt{19}\, i}{4},\ \frac{-3 - \sqrt{19}\, i}{4} \]
\[ 4x^2 + 6x + 7 = 0 \]
\[ D = 6^2 - 4\cdot4\cdot7 = 36 - 112 = -76 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{-76}}{8} \]
\[ x = \frac{-3 + \sqrt{19}\, i}{4}\quad\text{or}\quad x = \frac{-3 - \sqrt{19}\, i}{4} \]The parabola y = 4x² + 6x + 7
| x | y |
|---|---|
| -3.75 | 40.75 |
| -2.75 | 20.75 |
| -1.75 | 8.75 |
| -0.75 | 4.75 |
| 0.25 | 8.75 |
| 1.25 | 20.75 |
| 2.25 | 40.75 |
Questions
What are the solutions of 4x² + 6x + 7 = 0?
4x² + 6x + 7 = 0 has no real solutions. The two complex solutions are x = (-3 + √19 i)/4 and x = (-3 - √19 i)/4.
Does 4x² + 6x + 7 = 0 factor?
Not over the integers, because the discriminant -76 is negative. Use the quadratic formula.
What is the vertex of y = 4x² + 6x + 7?
(-3/4, 19/4). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = -3/2, product = c/a = 7/4.