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Solve 3x² - 9x + 12 = 0

3x² - 9x + 12 = 0 has no real solutions. The two complex solutions are x = (3 + √7 i)/2 and x = (3 - √7 i)/2.

x² +x += 0
3x2−9x+12=0⇒x=3+7 i2, 3−7 i2 (complex)3x^2 - 9x + 12 = 0 \Rightarrow x = \frac{3 + \sqrt{7}\, i}{2},\ \frac{3 - \sqrt{7}\, i}{2}\ \text{(complex)}
Discriminant D = -63

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 3x² - 9x + 12-2-1123451020304050vertexy = 3x² - 9x + 12
Graph of y = 3x² - 9x + 12. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (1.5, 5.25).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 3, b = -9, c = 12.

    3x2−9x+12=03x^2 - 9x + 12 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−9)2−4⋅3⋅12=81−144=−63D = (-9)^2 - 4\cdot3\cdot12 = 81 - 144 = -63
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=9±−636x = \frac{-b \pm \sqrt{D}}{2a} = \frac{9 \pm \sqrt{-63}}{6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=3+7 i2orx=3−7 i2x = \frac{3 + \sqrt{7}\, i}{2}\quad\text{or}\quad x = \frac{3 - \sqrt{7}\, i}{2}
LaTeX source of the formulas on this page
\[ 3x^2 - 9x + 12 = 0\ \Rightarrow\ x = \frac{3 + \sqrt{7}\, i}{2},\ \frac{3 - \sqrt{7}\, i}{2} \]
\[ 3x^2 - 9x + 12 = 0 \]
\[ D = (-9)^2 - 4\cdot3\cdot12 = 81 - 144 = -63 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{9 \pm \sqrt{-63}}{6} \]
\[ x = \frac{3 + \sqrt{7}\, i}{2}\quad\text{or}\quad x = \frac{3 - \sqrt{7}\, i}{2} \]

The parabola y = 3x² - 9x + 12

xy
-1.532.25
-0.517.25
0.58.25
1.55.25
2.58.25
3.517.25
4.532.25

Questions

What are the solutions of 3x² - 9x + 12 = 0?

3x² - 9x + 12 = 0 has no real solutions. The two complex solutions are x = (3 + √7 i)/2 and x = (3 - √7 i)/2.

Does 3x² - 9x + 12 = 0 factor?

Not over the integers, because the discriminant -63 is negative. Use the quadratic formula.

What is the vertex of y = 3x² - 9x + 12?

(3/2, 21/4). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 3, product = c/a = 4.

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