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Solve 3x² - 4x + 8 = 0

3x² - 4x + 8 = 0 has no real solutions. The two complex solutions are x = (2 + 2√5 i)/3 and x = (2 - 2√5 i)/3.

x² +x += 0
3x2−4x+8=0⇒x=2+25 i3, 2−25 i3 (complex)3x^2 - 4x + 8 = 0 \Rightarrow x = \frac{2 + 2\sqrt{5}\, i}{3},\ \frac{2 - 2\sqrt{5}\, i}{3}\ \text{(complex)}
Discriminant D = -80

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 3x² - 4x + 8-3-2-112341020304050vertexy = 3x² - 4x + 8
Graph of y = 3x² - 4x + 8. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (0.66666667, 6.6666667).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 3, b = -4, c = 8.

    3x2−4x+8=03x^2 - 4x + 8 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−4)2−4⋅3⋅8=16−96=−80D = (-4)^2 - 4\cdot3\cdot8 = 16 - 96 = -80
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=4±−806x = \frac{-b \pm \sqrt{D}}{2a} = \frac{4 \pm \sqrt{-80}}{6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=2+25 i3orx=2−25 i3x = \frac{2 + 2\sqrt{5}\, i}{3}\quad\text{or}\quad x = \frac{2 - 2\sqrt{5}\, i}{3}
LaTeX source of the formulas on this page
\[ 3x^2 - 4x + 8 = 0\ \Rightarrow\ x = \frac{2 + 2\sqrt{5}\, i}{3},\ \frac{2 - 2\sqrt{5}\, i}{3} \]
\[ 3x^2 - 4x + 8 = 0 \]
\[ D = (-4)^2 - 4\cdot3\cdot8 = 16 - 96 = -80 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{4 \pm \sqrt{-80}}{6} \]
\[ x = \frac{2 + 2\sqrt{5}\, i}{3}\quad\text{or}\quad x = \frac{2 - 2\sqrt{5}\, i}{3} \]

The parabola y = 3x² - 4x + 8

xy
-2.333333.666067
-1.333318.666267
-0.33339.6664667
0.66676.6666667
1.66679.6668667
2.666718.667067
3.666733.667267

Questions

What are the solutions of 3x² - 4x + 8 = 0?

3x² - 4x + 8 = 0 has no real solutions. The two complex solutions are x = (2 + 2√5 i)/3 and x = (2 - 2√5 i)/3.

Does 3x² - 4x + 8 = 0 factor?

Not over the integers, because the discriminant -80 is negative. Use the quadratic formula.

What is the vertex of y = 3x² - 4x + 8?

(2/3, 20/3). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 4/3, product = c/a = 8/3.

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