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Solve 3x² - 12x + 3 = 0

The solutions of 3x² - 12x + 3 = 0 are x = 2 + √3 or x = 2 - √3, that is x ≈ 3.7320508 and x ≈ 0.26794919.

x² +x += 0
3x2−12x+3=0⇒x=2+3, 2−33x^2 - 12x + 3 = 0 \Rightarrow x = 2 + \sqrt{3},\ 2 - \sqrt{3}
Discriminant D = 108 · x ≈ 3.73205, 0.267949

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 3x² - 12x + 3-2-1123456-1010203040x = 3.7320508x = 0.26794919vertexy = 3x² - 12x + 3
Graph of y = 3x² - 12x + 3. The curve crosses the x-axis at x = 3.7320508 and x = 0.26794919; the vertex is at (2, -9).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 3, b = -12, c = 3.

    3x2−12x+3=03x^2 - 12x + 3 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−12)2−4⋅3⋅3=144−36=108D = (-12)^2 - 4\cdot3\cdot3 = 144 - 36 = 108
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=12±1086x = \frac{-b \pm \sqrt{D}}{2a} = \frac{12 \pm \sqrt{108}}{6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=2+3orx=2−3x = 2 + \sqrt{3}\quad\text{or}\quad x = 2 - \sqrt{3}
  6. 6

    As decimals: x ≈ 3.7320508 and x ≈ 0.26794919.

  7. 7

    Check numerically: for x ≈ 3.7320508 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ 3x^2 - 12x + 3 = 0\ \Rightarrow\ x = 2 + \sqrt{3},\ 2 - \sqrt{3} \]
\[ 3x^2 - 12x + 3 = 0 \]
\[ D = (-12)^2 - 4\cdot3\cdot3 = 144 - 36 = 108 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{12 \pm \sqrt{108}}{6} \]
\[ x = 2 + \sqrt{3}\quad\text{or}\quad x = 2 - \sqrt{3} \]

The parabola y = 3x² - 12x + 3

xy
-118
03
1-6
2-9
3-6
43
518

Questions

What are the solutions of 3x² - 12x + 3 = 0?

The solutions of 3x² - 12x + 3 = 0 are x = 2 + √3 or x = 2 - √3, that is x ≈ 3.7320508 and x ≈ 0.26794919.

Does 3x² - 12x + 3 = 0 factor?

Not over the integers, because the discriminant 108 is not a perfect square. Use the quadratic formula.

What is the vertex of y = 3x² - 12x + 3?

(2, -9). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 4, product = c/a = 1.

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    Solve 3x² - 12x + 3 = 0: x = 2 + √3 or x = 2 - √3 (steps) | WordGPT