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Solve 3x² - 10x + 9 = 0

3x² - 10x + 9 = 0 has no real solutions. The two complex solutions are x = (5 + √2 i)/3 and x = (5 - √2 i)/3.

x² +x += 0
3x2−10x+9=0⇒x=5+2 i3, 5−2 i3 (complex)3x^2 - 10x + 9 = 0 \Rightarrow x = \frac{5 + \sqrt{2}\, i}{3},\ \frac{5 - \sqrt{2}\, i}{3}\ \text{(complex)}
Discriminant D = -8

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 3x² - 10x + 9-2-1123451020304050vertexy = 3x² - 10x + 9
Graph of y = 3x² - 10x + 9. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (1.6666667, 0.66666667).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 3, b = -10, c = 9.

    3x2−10x+9=03x^2 - 10x + 9 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−10)2−4⋅3⋅9=100−108=−8D = (-10)^2 - 4\cdot3\cdot9 = 100 - 108 = -8
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=10±−86x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{-8}}{6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=5+2 i3orx=5−2 i3x = \frac{5 + \sqrt{2}\, i}{3}\quad\text{or}\quad x = \frac{5 - \sqrt{2}\, i}{3}
LaTeX source of the formulas on this page
\[ 3x^2 - 10x + 9 = 0\ \Rightarrow\ x = \frac{5 + \sqrt{2}\, i}{3},\ \frac{5 - \sqrt{2}\, i}{3} \]
\[ 3x^2 - 10x + 9 = 0 \]
\[ D = (-10)^2 - 4\cdot3\cdot9 = 100 - 108 = -8 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{-8}}{6} \]
\[ x = \frac{5 + \sqrt{2}\, i}{3}\quad\text{or}\quad x = \frac{5 - \sqrt{2}\, i}{3} \]

The parabola y = 3x² - 10x + 9

xy
-1.333327.666067
-0.333312.666267
0.66673.6664667
1.66670.66666667
2.66673.6668667
3.666712.667067
4.666727.667267

Questions

What are the solutions of 3x² - 10x + 9 = 0?

3x² - 10x + 9 = 0 has no real solutions. The two complex solutions are x = (5 + √2 i)/3 and x = (5 - √2 i)/3.

Does 3x² - 10x + 9 = 0 factor?

Not over the integers, because the discriminant -8 is negative. Use the quadratic formula.

What is the vertex of y = 3x² - 10x + 9?

(5/3, 2/3). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 10/3, product = c/a = 3.

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