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Solve 3x² - 10x + 11 = 0

3x² - 10x + 11 = 0 has no real solutions. The two complex solutions are x = (5 + 2√2 i)/3 and x = (5 - 2√2 i)/3.

x² +x += 0
3x2−10x+11=0⇒x=5+22 i3, 5−22 i3 (complex)3x^2 - 10x + 11 = 0 \Rightarrow x = \frac{5 + 2\sqrt{2}\, i}{3},\ \frac{5 - 2\sqrt{2}\, i}{3}\ \text{(complex)}
Discriminant D = -32

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 3x² - 10x + 11-2-1123451020304050vertexy = 3x² - 10x + 11
Graph of y = 3x² - 10x + 11. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (1.6666667, 2.6666667).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 3, b = -10, c = 11.

    3x2−10x+11=03x^2 - 10x + 11 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−10)2−4⋅3⋅11=100−132=−32D = (-10)^2 - 4\cdot3\cdot11 = 100 - 132 = -32
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=10±−326x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{-32}}{6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=5+22 i3orx=5−22 i3x = \frac{5 + 2\sqrt{2}\, i}{3}\quad\text{or}\quad x = \frac{5 - 2\sqrt{2}\, i}{3}
LaTeX source of the formulas on this page
\[ 3x^2 - 10x + 11 = 0\ \Rightarrow\ x = \frac{5 + 2\sqrt{2}\, i}{3},\ \frac{5 - 2\sqrt{2}\, i}{3} \]
\[ 3x^2 - 10x + 11 = 0 \]
\[ D = (-10)^2 - 4\cdot3\cdot11 = 100 - 132 = -32 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{10 \pm \sqrt{-32}}{6} \]
\[ x = \frac{5 + 2\sqrt{2}\, i}{3}\quad\text{or}\quad x = \frac{5 - 2\sqrt{2}\, i}{3} \]

The parabola y = 3x² - 10x + 11

xy
-1.333329.666067
-0.333314.666267
0.66675.6664667
1.66672.6666667
2.66675.6668667
3.666714.667067
4.666729.667267

Questions

What are the solutions of 3x² - 10x + 11 = 0?

3x² - 10x + 11 = 0 has no real solutions. The two complex solutions are x = (5 + 2√2 i)/3 and x = (5 - 2√2 i)/3.

Does 3x² - 10x + 11 = 0 factor?

Not over the integers, because the discriminant -32 is negative. Use the quadratic formula.

What is the vertex of y = 3x² - 10x + 11?

(5/3, 8/3). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 10/3, product = c/a = 11/3.

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