Solve 3x² + 9x - 5 = 0
The solutions of 3x² + 9x - 5 = 0 are x = (-9 + √141)/6 or x = (-9 - √141)/6, that is x ≈ 0.47905701 and x ≈ -3.479057.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 3, b = 9, c = -5.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
The quadratic formula works for every quadratic:
- 5
Simplify (pull the square out of the root) to get the solutions:
- 6
As decimals: x ≈ 0.47905701 and x ≈ -3.479057.
- 7
Check numerically: for x ≈ 0.47905701 the left side is -8.8817842e-16 (zero up to rounding) ✓
LaTeX source of the formulas on this page
\[ 3x^2 + 9x - 5 = 0\ \Rightarrow\ x = \frac{-9 + \sqrt{141}}{6},\ \frac{-9 - \sqrt{141}}{6} \]
\[ 3x^2 + 9x - 5 = 0 \]
\[ D = 9^2 - 4\cdot3\cdot(-5) = 81 + 60 = 141 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-9 \pm \sqrt{141}}{6} \]
\[ x = \frac{-9 + \sqrt{141}}{6}\quad\text{or}\quad x = \frac{-9 - \sqrt{141}}{6} \]The parabola y = 3x² + 9x - 5
| x | y |
|---|---|
| -4.5 | 15.25 |
| -3.5 | 0.25 |
| -2.5 | -8.75 |
| -1.5 | -11.75 |
| -0.5 | -8.75 |
| 0.5 | 0.25 |
| 1.5 | 15.25 |
Questions
What are the solutions of 3x² + 9x - 5 = 0?
The solutions of 3x² + 9x - 5 = 0 are x = (-9 + √141)/6 or x = (-9 - √141)/6, that is x ≈ 0.47905701 and x ≈ -3.479057.
Does 3x² + 9x - 5 = 0 factor?
Not over the integers, because the discriminant 141 is not a perfect square. Use the quadratic formula.
What is the vertex of y = 3x² + 9x - 5?
(-3/2, -47/4). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = -3, product = c/a = -5/3.