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Solve 3x² + 9x + 9 = 0

3x² + 9x + 9 = 0 has no real solutions. The two complex solutions are x = (-3 + √3 i)/2 and x = (-3 - √3 i)/2.

x² +x += 0
3x2+9x+9=0⇒x=−3+3 i2, −3−3 i2 (complex)3x^2 + 9x + 9 = 0 \Rightarrow x = \frac{-3 + \sqrt{3}\, i}{2},\ \frac{-3 - \sqrt{3}\, i}{2}\ \text{(complex)}
Discriminant D = -27

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 3x² + 9x + 9-5-4-3-2-1121020304050vertexy = 3x² + 9x + 9
Graph of y = 3x² + 9x + 9. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (-1.5, 2.25).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 3, b = 9, c = 9.

    3x2+9x+9=03x^2 + 9x + 9 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=92−4⋅3⋅9=81−108=−27D = 9^2 - 4\cdot3\cdot9 = 81 - 108 = -27
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−9±−276x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-9 \pm \sqrt{-27}}{6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−3+3 i2orx=−3−3 i2x = \frac{-3 + \sqrt{3}\, i}{2}\quad\text{or}\quad x = \frac{-3 - \sqrt{3}\, i}{2}
LaTeX source of the formulas on this page
\[ 3x^2 + 9x + 9 = 0\ \Rightarrow\ x = \frac{-3 + \sqrt{3}\, i}{2},\ \frac{-3 - \sqrt{3}\, i}{2} \]
\[ 3x^2 + 9x + 9 = 0 \]
\[ D = 9^2 - 4\cdot3\cdot9 = 81 - 108 = -27 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-9 \pm \sqrt{-27}}{6} \]
\[ x = \frac{-3 + \sqrt{3}\, i}{2}\quad\text{or}\quad x = \frac{-3 - \sqrt{3}\, i}{2} \]

The parabola y = 3x² + 9x + 9

xy
-4.529.25
-3.514.25
-2.55.25
-1.52.25
-0.55.25
0.514.25
1.529.25

Questions

What are the solutions of 3x² + 9x + 9 = 0?

3x² + 9x + 9 = 0 has no real solutions. The two complex solutions are x = (-3 + √3 i)/2 and x = (-3 - √3 i)/2.

Does 3x² + 9x + 9 = 0 factor?

Not over the integers, because the discriminant -27 is negative. Use the quadratic formula.

What is the vertex of y = 3x² + 9x + 9?

(-3/2, 9/4). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -3, product = c/a = 3.

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