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Solve 3x² + 8x - 1 = 0

The solutions of 3x² + 8x - 1 = 0 are x = (-4 + √19)/3 or x = (-4 - √19)/3, that is x ≈ 0.11963298 and x ≈ -2.7862996.

x² +x += 0
3x2+8x−1=0⇒x=−4+193, −4−1933x^2 + 8x - 1 = 0 \Rightarrow x = \frac{-4 + \sqrt{19}}{3},\ \frac{-4 - \sqrt{19}}{3}
Discriminant D = 76 · x ≈ 0.119633, -2.7863

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 3x² + 8x - 1-5-4-3-2-112-1010203040x = 0.11963298x = -2.7862996vertexy = 3x² + 8x - 1
Graph of y = 3x² + 8x - 1. The curve crosses the x-axis at x = 0.11963298 and x = -2.7862996; the vertex is at (-1.3333333, -6.3333333).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 3, b = 8, c = -1.

    3x2+8x−1=03x^2 + 8x - 1 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=82−4⋅3⋅(−1)=64+12=76D = 8^2 - 4\cdot3\cdot(-1) = 64 + 12 = 76
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−8±766x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{76}}{6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−4+193orx=−4−193x = \frac{-4 + \sqrt{19}}{3}\quad\text{or}\quad x = \frac{-4 - \sqrt{19}}{3}
  6. 6

    As decimals: x ≈ 0.11963298 and x ≈ -2.7862996.

  7. 7

    Check numerically: for x ≈ 0.11963298 the left side is 1.110223e-15 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ 3x^2 + 8x - 1 = 0\ \Rightarrow\ x = \frac{-4 + \sqrt{19}}{3},\ \frac{-4 - \sqrt{19}}{3} \]
\[ 3x^2 + 8x - 1 = 0 \]
\[ D = 8^2 - 4\cdot3\cdot(-1) = 64 + 12 = 76 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{76}}{6} \]
\[ x = \frac{-4 + \sqrt{19}}{3}\quad\text{or}\quad x = \frac{-4 - \sqrt{19}}{3} \]

The parabola y = 3x² + 8x - 1

xy
-4.333320.666067
-3.33335.6662667
-2.3333-3.3335333
-1.3333-6.3333333
-0.3333-3.3331333
0.66675.6670667
1.666720.667267

Questions

What are the solutions of 3x² + 8x - 1 = 0?

The solutions of 3x² + 8x - 1 = 0 are x = (-4 + √19)/3 or x = (-4 - √19)/3, that is x ≈ 0.11963298 and x ≈ -2.7862996.

Does 3x² + 8x - 1 = 0 factor?

Not over the integers, because the discriminant 76 is not a perfect square. Use the quadratic formula.

What is the vertex of y = 3x² + 8x - 1?

(-4/3, -19/3). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -8/3, product = c/a = -1/3.

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    Solve 3x² + 8x - 1 = 0: x = (-4 + √19)/3 or x = (-4 - √19)/3 (steps) | WordGPT