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Solve 3x² + 6x - 6 = 0

The solutions of 3x² + 6x - 6 = 0 are x = -1 + √3 or x = -1 - √3, that is x ≈ 0.73205081 and x ≈ -2.7320508.

x² +x += 0
3x2+6x−6=0⇒x=−1+3, −1−33x^2 + 6x - 6 = 0 \Rightarrow x = -1 + \sqrt{3},\ -1 - \sqrt{3}
Discriminant D = 108 · x ≈ 0.732051, -2.73205

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 3x² + 6x - 6-5-4-3-2-1123-1010203040x = 0.73205081x = -2.7320508vertexy = 3x² + 6x - 6
Graph of y = 3x² + 6x - 6. The curve crosses the x-axis at x = 0.73205081 and x = -2.7320508; the vertex is at (-1, -9).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 3, b = 6, c = -6.

    3x2+6x−6=03x^2 + 6x - 6 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=62−4⋅3⋅(−6)=36+72=108D = 6^2 - 4\cdot3\cdot(-6) = 36 + 72 = 108
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−6±1086x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{108}}{6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−1+3orx=−1−3x = -1 + \sqrt{3}\quad\text{or}\quad x = -1 - \sqrt{3}
  6. 6

    As decimals: x ≈ 0.73205081 and x ≈ -2.7320508.

  7. 7

    Check numerically: for x ≈ 0.73205081 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ 3x^2 + 6x - 6 = 0\ \Rightarrow\ x = -1 + \sqrt{3},\ -1 - \sqrt{3} \]
\[ 3x^2 + 6x - 6 = 0 \]
\[ D = 6^2 - 4\cdot3\cdot(-6) = 36 + 72 = 108 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{108}}{6} \]
\[ x = -1 + \sqrt{3}\quad\text{or}\quad x = -1 - \sqrt{3} \]

The parabola y = 3x² + 6x - 6

xy
-418
-33
-2-6
-1-9
0-6
13
218

Questions

What are the solutions of 3x² + 6x - 6 = 0?

The solutions of 3x² + 6x - 6 = 0 are x = -1 + √3 or x = -1 - √3, that is x ≈ 0.73205081 and x ≈ -2.7320508.

Does 3x² + 6x - 6 = 0 factor?

Not over the integers, because the discriminant 108 is not a perfect square. Use the quadratic formula.

What is the vertex of y = 3x² + 6x - 6?

(-1, -9). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -2, product = c/a = -2.

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    Solve 3x² + 6x - 6 = 0: x = -1 + √3 or x = -1 - √3 (steps) | WordGPT