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Solve 3x² + 10x - 8 = 0

The solutions of 3x² + 10x - 8 = 0 are x = 2/3 or x = -4.

x² +x += 0
3x2+10x−8=0⇒x=23, −43x^2 + 10x - 8 = 0 \Rightarrow x = \frac{2}{3},\ -4
Discriminant D = 196 · x ≈ 0.666667, -4

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = 3x² + 10x - 8-6-5-4-3-2-1123-20-101020304050x = 0.66666667x = -4vertexy = 3x² + 10x - 8
Graph of y = 3x² + 10x - 8. The curve crosses the x-axis at x = 0.66666667 and x = -4; the vertex is at (-1.6666667, -16.333333).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 3, b = 10, c = -8.

    3x2+10x−8=03x^2 + 10x - 8 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=102−4⋅3⋅(−8)=100+96=196D = 10^2 - 4\cdot3\cdot(-8) = 100 + 96 = 196
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    Method 1, factoring. The roots are rational, so the left side factors:

    (3x−2)(x+4)=0\left(3x - 2\right)\left(x + 4\right) = 0
  5. 5

    A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:

    3x−2=0⇒x=23x+4=0⇒x=−43x - 2 = 0 \Rightarrow x = \frac{2}{3}\qquad x + 4 = 0 \Rightarrow x = -4
  6. 6

    Method 2, The quadratic formula works for every quadratic:

    x=−b±D2a=−10±1966x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-10 \pm \sqrt{196}}{6}
  7. 7

    Simplify to get the solutions:

    x=23orx=−4x = \frac{2}{3}\quad\text{or}\quad x = -4
  8. 8

    Check by putting x = 2/3 back in: a·x² + b·x + c = 3·(4/9) + 10·(2/3) + (-8) = 0 ✓

LaTeX source of the formulas on this page
\[ 3x^2 + 10x - 8 = 0\ \Rightarrow\ x = \frac{2}{3},\ -4 \]
\[ 3x^2 + 10x - 8 = 0 \]
\[ D = 10^2 - 4\cdot3\cdot(-8) = 100 + 96 = 196 \]
\[ \left(3x - 2\right)\left(x + 4\right) = 0 \]
\[ 3x - 2 = 0 \Rightarrow x = \frac{2}{3}\qquad x + 4 = 0 \Rightarrow x = -4 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-10 \pm \sqrt{196}}{6} \]
\[ x = \frac{2}{3}\quad\text{or}\quad x = -4 \]

The parabola y = 3x² + 10x - 8

xy
-4.666710.667267
-3.6667-4.3329333
-2.6667-13.333133
-1.6667-16.333333
-0.6667-13.333533
0.3333-4.3337333
1.333310.666067

Questions

What are the solutions of 3x² + 10x - 8 = 0?

The solutions of 3x² + 10x - 8 = 0 are x = 2/3 or x = -4.

Does 3x² + 10x - 8 = 0 factor?

Yes: (3x-2)(x+4) = 0.

What is the vertex of y = 3x² + 10x - 8?

(-5/3, -49/3). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -10/3, product = c/a = -8/3.

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