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Solve 2x² - 8x + 6 = 0

The solutions of 2x² - 8x + 6 = 0 are x = 3 or x = 1.

x² +x += 0
2x2−8x+6=0⇒x=3, 12x^2 - 8x + 6 = 0 \Rightarrow x = 3,\ 1
Discriminant D = 16 · x ≈ 3, 1

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = 2x² - 8x + 6-112345-55101520x = 3x = 1vertexy = 2x² - 8x + 6
Graph of y = 2x² - 8x + 6. The curve crosses the x-axis at x = 3 and x = 1; the vertex is at (2, -2).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 2, b = -8, c = 6.

    2x2−8x+6=02x^2 - 8x + 6 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−8)2−4⋅2⋅6=64−48=16D = (-8)^2 - 4\cdot2\cdot6 = 64 - 48 = 16
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    Method 1, factoring. The roots are rational, so the left side factors:

    2(x−3)(x−1)=02\left(x - 3\right)\left(x - 1\right) = 0
  5. 5

    A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:

    x−3=0⇒x=3x−1=0⇒x=1x - 3 = 0 \Rightarrow x = 3\qquad x - 1 = 0 \Rightarrow x = 1
  6. 6

    Method 2, The quadratic formula works for every quadratic:

    x=−b±D2a=8±164x = \frac{-b \pm \sqrt{D}}{2a} = \frac{8 \pm \sqrt{16}}{4}
  7. 7

    Simplify to get the solutions:

    x=3orx=1x = 3\quad\text{or}\quad x = 1
  8. 8

    Check by putting x = 3 back in: a·x² + b·x + c = 2·(9) + (-8)·(3) + 6 = 0 ✓

LaTeX source of the formulas on this page
\[ 2x^2 - 8x + 6 = 0\ \Rightarrow\ x = 3,\ 1 \]
\[ 2x^2 - 8x + 6 = 0 \]
\[ D = (-8)^2 - 4\cdot2\cdot6 = 64 - 48 = 16 \]
\[ 2\left(x - 3\right)\left(x - 1\right) = 0 \]
\[ x - 3 = 0 \Rightarrow x = 3\qquad x - 1 = 0 \Rightarrow x = 1 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{8 \pm \sqrt{16}}{4} \]
\[ x = 3\quad\text{or}\quad x = 1 \]

The parabola y = 2x² - 8x + 6

xy
-116
06
10
2-2
30
46
516

Questions

What are the solutions of 2x² - 8x + 6 = 0?

The solutions of 2x² - 8x + 6 = 0 are x = 3 or x = 1.

Does 2x² - 8x + 6 = 0 factor?

Yes: 2(x-3)(x-1) = 0.

What is the vertex of y = 2x² - 8x + 6?

(2, -2). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 4, product = c/a = 3.

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