Solve 2x² - 8x = 0
The solutions of 2x² - 8x = 0 are x = 4 or x = 0.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 2, b = -8, c = 0.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
Method 1, factoring. The roots are rational, so the left side factors:
- 5
A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:
- 6
Method 2, The quadratic formula works for every quadratic:
- 7
Simplify to get the solutions:
- 8
Check by putting x = 4 back in: a·x² + b·x + c = 2·(16) + (-8)·(4) + 0 = 0 ✓
LaTeX source of the formulas on this page
\[ 2x^2 - 8x = 0\ \Rightarrow\ x = 4,\ 0 \]
\[ 2x^2 - 8x = 0 \]
\[ D = (-8)^2 - 4\cdot2\cdot0 = 64 + 0 = 64 \]
\[ 2\left(x - 4\right)\left(x\right) = 0 \]
\[ x - 4 = 0 \Rightarrow x = 4\qquad x = 0 \Rightarrow x = 0 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{8 \pm \sqrt{64}}{4} \]
\[ x = 4\quad\text{or}\quad x = 0 \]The parabola y = 2x² - 8x
| x | y |
|---|---|
| -1 | 10 |
| 0 | 0 |
| 1 | -6 |
| 2 | -8 |
| 3 | -6 |
| 4 | 0 |
| 5 | 10 |
Questions
What are the solutions of 2x² - 8x = 0?
The solutions of 2x² - 8x = 0 are x = 4 or x = 0.
Does 2x² - 8x = 0 factor?
Yes: 2(x-4)(x) = 0.
What is the vertex of y = 2x² - 8x?
(2, -8). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = 4, product = c/a = 0.