Solve 2x² - 7x + 12 = 0
2x² - 7x + 12 = 0 has no real solutions. The two complex solutions are x = (7 + √47 i)/4 and x = (7 - √47 i)/4.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 2, b = -7, c = 12.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is negative, so there are no real solutions; the two solutions are complex numbers.
- 4
The quadratic formula works for every quadratic:
- 5
Simplify (pull the square out of the root) to get the solutions:
LaTeX source of the formulas on this page
\[ 2x^2 - 7x + 12 = 0\ \Rightarrow\ x = \frac{7 + \sqrt{47}\, i}{4},\ \frac{7 - \sqrt{47}\, i}{4} \]
\[ 2x^2 - 7x + 12 = 0 \]
\[ D = (-7)^2 - 4\cdot2\cdot12 = 49 - 96 = -47 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{7 \pm \sqrt{-47}}{4} \]
\[ x = \frac{7 + \sqrt{47}\, i}{4}\quad\text{or}\quad x = \frac{7 - \sqrt{47}\, i}{4} \]The parabola y = 2x² - 7x + 12
| x | y |
|---|---|
| -1.25 | 23.875 |
| -0.25 | 13.875 |
| 0.75 | 7.875 |
| 1.75 | 5.875 |
| 2.75 | 7.875 |
| 3.75 | 13.875 |
| 4.75 | 23.875 |
Questions
What are the solutions of 2x² - 7x + 12 = 0?
2x² - 7x + 12 = 0 has no real solutions. The two complex solutions are x = (7 + √47 i)/4 and x = (7 - √47 i)/4.
Does 2x² - 7x + 12 = 0 factor?
Not over the integers, because the discriminant -47 is negative. Use the quadratic formula.
What is the vertex of y = 2x² - 7x + 12?
(7/4, 47/8). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = 7/2, product = c/a = 6.