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Solve 2x² - 5x + 11 = 0

2x² - 5x + 11 = 0 has no real solutions. The two complex solutions are x = (5 + 3√7 i)/4 and x = (5 - 3√7 i)/4.

x² +x += 0
2x2−5x+11=0⇒x=5+37 i4, 5−37 i4 (complex)2x^2 - 5x + 11 = 0 \Rightarrow x = \frac{5 + 3\sqrt{7}\, i}{4},\ \frac{5 - 3\sqrt{7}\, i}{4}\ \text{(complex)}
Discriminant D = -63

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 2x² - 5x + 11-2-112345510152025303540vertexy = 2x² - 5x + 11
Graph of y = 2x² - 5x + 11. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (1.25, 7.875).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 2, b = -5, c = 11.

    2x2−5x+11=02x^2 - 5x + 11 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−5)2−4⋅2⋅11=25−88=−63D = (-5)^2 - 4\cdot2\cdot11 = 25 - 88 = -63
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=5±−634x = \frac{-b \pm \sqrt{D}}{2a} = \frac{5 \pm \sqrt{-63}}{4}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=5+37 i4orx=5−37 i4x = \frac{5 + 3\sqrt{7}\, i}{4}\quad\text{or}\quad x = \frac{5 - 3\sqrt{7}\, i}{4}
LaTeX source of the formulas on this page
\[ 2x^2 - 5x + 11 = 0\ \Rightarrow\ x = \frac{5 + 3\sqrt{7}\, i}{4},\ \frac{5 - 3\sqrt{7}\, i}{4} \]
\[ 2x^2 - 5x + 11 = 0 \]
\[ D = (-5)^2 - 4\cdot2\cdot11 = 25 - 88 = -63 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{5 \pm \sqrt{-63}}{4} \]
\[ x = \frac{5 + 3\sqrt{7}\, i}{4}\quad\text{or}\quad x = \frac{5 - 3\sqrt{7}\, i}{4} \]

The parabola y = 2x² - 5x + 11

xy
-1.7525.875
-0.7515.875
0.259.875
1.257.875
2.259.875
3.2515.875
4.2525.875

Questions

What are the solutions of 2x² - 5x + 11 = 0?

2x² - 5x + 11 = 0 has no real solutions. The two complex solutions are x = (5 + 3√7 i)/4 and x = (5 - 3√7 i)/4.

Does 2x² - 5x + 11 = 0 factor?

Not over the integers, because the discriminant -63 is negative. Use the quadratic formula.

What is the vertex of y = 2x² - 5x + 11?

(5/4, 63/8). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 5/2, product = c/a = 11/2.

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