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Solve 2x² - x - 4 = 0

The solutions of 2x² - x - 4 = 0 are x = (1 + √33)/4 or x = (1 - √33)/4, that is x ≈ 1.6861407 and x ≈ -1.1861407.

x² +x += 0
2x2−x−4=0⇒x=1+334, 1−3342x^2 - x - 4 = 0 \Rightarrow x = \frac{1 + \sqrt{33}}{4},\ \frac{1 - \sqrt{33}}{4}
Discriminant D = 33 · x ≈ 1.68614, -1.18614

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 2x² - x - 4-3-2-11234-5510152025x = 1.6861407x = -1.1861407vertexy = 2x² - x - 4
Graph of y = 2x² - x - 4. The curve crosses the x-axis at x = 1.6861407 and x = -1.1861407; the vertex is at (0.25, -4.125).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 2, b = -1, c = -4.

    2x2−x−4=02x^2 - x - 4 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−1)2−4⋅2⋅(−4)=1+32=33D = (-1)^2 - 4\cdot2\cdot(-4) = 1 + 32 = 33
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=1±334x = \frac{-b \pm \sqrt{D}}{2a} = \frac{1 \pm \sqrt{33}}{4}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=1+334orx=1−334x = \frac{1 + \sqrt{33}}{4}\quad\text{or}\quad x = \frac{1 - \sqrt{33}}{4}
  6. 6

    As decimals: x ≈ 1.6861407 and x ≈ -1.1861407.

  7. 7

    Check numerically: for x ≈ 1.6861407 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ 2x^2 - x - 4 = 0\ \Rightarrow\ x = \frac{1 + \sqrt{33}}{4},\ \frac{1 - \sqrt{33}}{4} \]
\[ 2x^2 - x - 4 = 0 \]
\[ D = (-1)^2 - 4\cdot2\cdot(-4) = 1 + 32 = 33 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{1 \pm \sqrt{33}}{4} \]
\[ x = \frac{1 + \sqrt{33}}{4}\quad\text{or}\quad x = \frac{1 - \sqrt{33}}{4} \]

The parabola y = 2x² - x - 4

xy
-2.7513.875
-1.753.875
-0.75-2.125
0.25-4.125
1.25-2.125
2.253.875
3.2513.875

Questions

What are the solutions of 2x² - x - 4 = 0?

The solutions of 2x² - x - 4 = 0 are x = (1 + √33)/4 or x = (1 - √33)/4, that is x ≈ 1.6861407 and x ≈ -1.1861407.

Does 2x² - x - 4 = 0 factor?

Not over the integers, because the discriminant 33 is not a perfect square. Use the quadratic formula.

What is the vertex of y = 2x² - x - 4?

(1/4, -33/8). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 1/2, product = c/a = -2.

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    Solve 2x² - x - 4 = 0: x = (1 + √33)/4 or x = (1 - √33)/4 (steps) | WordGPT