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Solve 2x² - 11x + 5 = 0

The solutions of 2x² - 11x + 5 = 0 are x = 5 or x = 1/2.

x² +x += 0
2x2−11x+5=0⇒x=5, 122x^2 - 11x + 5 = 0 \Rightarrow x = 5,\ \frac{1}{2}
Discriminant D = 81 · x ≈ 5, 0.5

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = 2x² - 11x + 5-2-11234567-10102030x = 5x = 0.5vertexy = 2x² - 11x + 5
Graph of y = 2x² - 11x + 5. The curve crosses the x-axis at x = 5 and x = 0.5; the vertex is at (2.75, -10.125).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 2, b = -11, c = 5.

    2x2−11x+5=02x^2 - 11x + 5 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−11)2−4⋅2⋅5=121−40=81D = (-11)^2 - 4\cdot2\cdot5 = 121 - 40 = 81
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    Method 1, factoring. The roots are rational, so the left side factors:

    (x−5)(2x−1)=0\left(x - 5\right)\left(2x - 1\right) = 0
  5. 5

    A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:

    x−5=0⇒x=52x−1=0⇒x=12x - 5 = 0 \Rightarrow x = 5\qquad 2x - 1 = 0 \Rightarrow x = \frac{1}{2}
  6. 6

    Method 2, The quadratic formula works for every quadratic:

    x=−b±D2a=11±814x = \frac{-b \pm \sqrt{D}}{2a} = \frac{11 \pm \sqrt{81}}{4}
  7. 7

    Simplify to get the solutions:

    x=5orx=12x = 5\quad\text{or}\quad x = \frac{1}{2}
  8. 8

    Check by putting x = 5 back in: a·x² + b·x + c = 2·(25) + (-11)·(5) + 5 = 0 ✓

LaTeX source of the formulas on this page
\[ 2x^2 - 11x + 5 = 0\ \Rightarrow\ x = 5,\ \frac{1}{2} \]
\[ 2x^2 - 11x + 5 = 0 \]
\[ D = (-11)^2 - 4\cdot2\cdot5 = 121 - 40 = 81 \]
\[ \left(x - 5\right)\left(2x - 1\right) = 0 \]
\[ x - 5 = 0 \Rightarrow x = 5\qquad 2x - 1 = 0 \Rightarrow x = \frac{1}{2} \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{11 \pm \sqrt{81}}{4} \]
\[ x = 5\quad\text{or}\quad x = \frac{1}{2} \]

The parabola y = 2x² - 11x + 5

xy
-0.257.875
0.75-2.125
1.75-8.125
2.75-10.125
3.75-8.125
4.75-2.125
5.757.875

Questions

What are the solutions of 2x² - 11x + 5 = 0?

The solutions of 2x² - 11x + 5 = 0 are x = 5 or x = 1/2.

Does 2x² - 11x + 5 = 0 factor?

Yes: (x-5)(2x-1) = 0.

What is the vertex of y = 2x² - 11x + 5?

(11/4, -81/8). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 11/2, product = c/a = 5/2.

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