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Solve 2x² + 9x + 1 = 0

The solutions of 2x² + 9x + 1 = 0 are x = (-9 + √73)/4 or x = (-9 - √73)/4, that is x ≈ -0.11399906 and x ≈ -4.3860009.

x² +x += 0
2x2+9x+1=0⇒x=−9+734, −9−7342x^2 + 9x + 1 = 0 \Rightarrow x = \frac{-9 + \sqrt{73}}{4},\ \frac{-9 - \sqrt{73}}{4}
Discriminant D = 73 · x ≈ -0.113999, -4.386

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = 2x² + 9x + 1-6-5-4-3-2-112-10102030x = -0.11399906x = -4.3860009vertexy = 2x² + 9x + 1
Graph of y = 2x² + 9x + 1. The curve crosses the x-axis at x = -0.11399906 and x = -4.3860009; the vertex is at (-2.25, -9.125).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 2, b = 9, c = 1.

    2x2+9x+1=02x^2 + 9x + 1 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=92−4⋅2⋅1=81−8=73D = 9^2 - 4\cdot2\cdot1 = 81 - 8 = 73
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−9±734x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-9 \pm \sqrt{73}}{4}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−9+734orx=−9−734x = \frac{-9 + \sqrt{73}}{4}\quad\text{or}\quad x = \frac{-9 - \sqrt{73}}{4}
  6. 6

    As decimals: x ≈ -0.11399906 and x ≈ -4.3860009.

  7. 7

    Check numerically: for x ≈ -0.11399906 the left side is -1.7763568e-15 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ 2x^2 + 9x + 1 = 0\ \Rightarrow\ x = \frac{-9 + \sqrt{73}}{4},\ \frac{-9 - \sqrt{73}}{4} \]
\[ 2x^2 + 9x + 1 = 0 \]
\[ D = 9^2 - 4\cdot2\cdot1 = 81 - 8 = 73 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-9 \pm \sqrt{73}}{4} \]
\[ x = \frac{-9 + \sqrt{73}}{4}\quad\text{or}\quad x = \frac{-9 - \sqrt{73}}{4} \]

The parabola y = 2x² + 9x + 1

xy
-5.258.875
-4.25-1.125
-3.25-7.125
-2.25-9.125
-1.25-7.125
-0.25-1.125
0.758.875

Questions

What are the solutions of 2x² + 9x + 1 = 0?

The solutions of 2x² + 9x + 1 = 0 are x = (-9 + √73)/4 or x = (-9 - √73)/4, that is x ≈ -0.11399906 and x ≈ -4.3860009.

Does 2x² + 9x + 1 = 0 factor?

Not over the integers, because the discriminant 73 is not a perfect square. Use the quadratic formula.

What is the vertex of y = 2x² + 9x + 1?

(-9/4, -73/8). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -9/2, product = c/a = 1/2.

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    Solve 2x² + 9x + 1 = 0: x = (-9 + √73)/4 or x = (-9 - √73)/4 (steps) | WordGPT